Question

我试图在C＃中创建这个JSON字符串

[
  {
    accountId = 123,
    reportType = 1,
    reportTypeDesc = "Daily"
  },
  {
    accountId = 123,
    reportType = 1,
    reportTypeDesc = "Daily"
  },
  {
    accountId = 123,
    reportType = 1,
    reportTypeDesc = "Daily"
  }
]

我试过这种方式来做这个json，这是我的代码：

    var body = new []

            new
            {
                accountId = 123,
                reportType = 1,
                reportTypeDesc = "Daily"
            },
               new
            {
                accountId = 123,
                reportType = 1,
                reportTypeDesc = "Daily"
            },
               new
            {
               accountId = 123,
               reportType = 1,
               reportTypeDesc = "Daily"
            },

但我在＆＃34; new []＆＃34;中有编译错误。区域

制作这个Json的正确方法是什么？我尝试了很多不同的变化，但没有任何作用

Answer 1

尝试使用newtonsoft Json.NET，请参阅：

var body = new object []{
  new
  {
    accountId = 123,
    reportType = 1,
    reportTypeDesc = "Daily"
  },
 new
  {
      accountId = 123,
      reportType = 1,
      reportTypeDesc = "Daily"
  },
 new
  {
     accountId = 123,
     reportType = 1,
     reportTypeDesc = "Daily"
    },
};
var jsonBody = JsonConvert.SerializeObject(body);

在my .NET Fiddle中查看它。

Answer 2

在Json或c#中使用VB.Net解决方法的最佳方法是拥有一个像Newtonsoft.Json这样的优秀图书馆。这将使您的整个工作更轻松，更快捷。所以，只需下载该库并尝试编码。

<强>解决方法

public class MainClass
{
    public class Items
    {
        public int accountId, reportType;
        public string reportTypeDesc;
        public Items()
        {

        }
        public Items(int accountId, int reportType, string reportTypeDesc)
        {
            this.accountId = accountId;
            this.reportType = reportType;
            this.reportTypeDesc = reportTypeDesc;
        }
    }
    public List<Items> allItems = new List<Items>();
    public string toJson() =>
        JsonConvert.SerializeObject(allItems);
}

<强>执行

private void Form1_Load(object sender, EventArgs e)
    {
        MainClass m = new MainClass();
        m.allItems.Add(new MainClass.Items(123, 1, "Daily"));
        m.allItems.Add(new MainClass.Items(123, 1, "Daily"));
        m.allItems.Add(new MainClass.Items(123, 1, "Daily"));
        string json = m.toJson();
        richTextBox1.AppendText(json);
    }

创建复杂的JSON字符串

2 个答案: