我搜索了转置和支点但却找不到这样的东西。 输入表:
+-----+-------+-------+-------+
| TID | TP1 | TP2 | TP3 |
+-----+-------+-------+-------+
| A | link1 | link1 | link3 |
| B | link3 | | |
| C | link2 | | |
+-----+-------+-------+-------+
必需的输出表:
+-----+--------+-------+
| TID | TP Num | REF |
+-----+--------+-------+
| A | 1 | link1 |
| A | 2 | link1 |
| A | 3 | link3 |
| B | 1 | link3 |
| C | 1 | link2 |
+-----+--------+-------+
答案 0 :(得分:0)
这有点复杂,您需要使用union all来获得垂直表示,然后使用用户定义的变量获取nums的内容
dtbl = new DataTable();
dtbl.Columns.Add("Ad.No", typeof(String)); alignment[0] = 'C'; width[1] = 40;
dtbl.Columns.Add("AdmissionDate", typeof(String)); alignment[1] = 'C'; width[2] = 50;
dtbl.Columns.Add("Name", typeof(String)); alignment[2] = 'L'; width[3] = 100;
dtbl.Columns.Add("Class", typeof(String)); alignment[3] = 'C'; width[5] = 40;
for (int i = model.FromYear; i <= model.ToYear; i++)
{
for (int j = model.FromMonth; j <= model.ToMonth; j++)
{
for (int k = model.FromDay; k <= model.ToDay; k++)
{
dtbl.Columns.Add(Common.CommonUtility.GetShortMonthName(j)+" "+k, typeof(String)); alignment[4] = 'C'; width[5] = 40;
}
}
for (int i = model.FromYear; i <= model.ToYear; i++)
{
for (int j = model.FromMonth; j <= model.ToMonth; j++)
{
for (int k = model.FromDay; k <= model.ToDay; k++)
{
// dtbl.Rows.Add(dt[j]=std.value);
// foreach (var r in std.value){
dtbl.Rows.Add(dt["Ad.No"] = std.AdmissionNo, dt["AdmissionDate"] = Convert.ToDateTime(std.date.ToString()).ToString("dd/MM/yyyy"), dt["Class"] = std.Class, dt["Name"] = std.StudentName,dt[j]=std.value);
}
}