r if语句返回级别数而不是级别文本

Question

我有一张如下图所示的表格，我试图使用简单的if语句仅在食物是“橘子”的情况下返回国家名称。第3列是期望的结果，第4列是我在R中得到的。

在excel中，公式为：

=IF(A2="Oranges",B2,"n/a")

我使用以下r代码生成“oranges_country”变量：

table$oranges_country <- ifelse (Food == "Oranges", Country , "n/a")

[根据上图]代码返回“国家”级别列表中级别（例如6）的编号，而不是“国家”本身（例如“西班牙”）。我理解它来自何处（提取中的位置如下），但特别是当使用多个嵌套的if语句时，这是一种痛苦。

levels(Country)
[1] "California"  "Ecuador"     "France"      "New Zealand" "Peru"        "Spain"       "UK"  

必须有一个简单的方法来改变这个???

根据评论中的要求：dput（table）输出如下： dput(table) structure(list(Food = structure(c(1L, 1L, 3L, 1L, 1L, 3L, 3L, 2L, 2L), .Label = c("Apples", "Bananas", "Oranges"), class = "factor"), Country = structure(c(3L, 7L, 6L, 4L, 7L, 6L, 1L, 5L, 2L), .Label = c("California", "Ecuador", "France", "New Zealand", "Peru", "Spain", "UK" ), class = "factor"), Desired_If.Outcome = structure(c(2L, 2L, 3L, 2L, 2L, 3L, 1L, 2L, 2L), .Label = c("California", "n/a", "Spain"), class = "factor"), oranges_country = c("n/a", "n/a", "6", "n/a", "n/a", "6", "1", "n/a", "n/a"), desiredcolumn = c(NA, NA, 6L, NA, NA, 6L, 1L, NA, NA)), .Names = c("Food", "Country", "Desired_If.Outcome", "oranges_country", "desiredcolumn"), row.names = c(NA, -9L), class = "data.frame")

Answer 1

试试这个（如果您的表名为table）：

table[table$Food=="Oragnes", ]

Answer 2

尝试ifelse循环。首先，将Table $ Country更改为character（）

 table$Country<-as.character(Table$Country)
 table$desiredcolumn<-ifelse(table$Food == "Oranges", table$Country, NA)

这是我的版本：

Food<-c("Ap","Ap","Or","Ap","Ap","Or","Or","Ba","Ba")
Country<-c("Fra","UK","Sp","Nz","UK","Sp","Cal","Per","Eq")
Table<-cbind(Food,Country)
Table<-data.frame(Table)
Table$Country<-as.character(Table$Country)
Table$DC<-ifelse(Table$Food=="Or", Table$Country, NA)
Table

Food Country   DC
1   Ap     Fra <NA>
2   Ap      UK <NA>
3   Or      Sp   Sp
4   Ap      Nz <NA>
5   Ap      UK <NA>
6   Or      Sp   Sp
7   Or     Cal  Cal
8   Ba     Per <NA>
9   Ba      Eq <NA>