Question

当我尝试运行我的项目时，我收到错误

Caused by: java.lang.IllegalArgumentException: Servlet mapping specifies an unknown servlet name dispatcher
    at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3156)
    at org.apache.catalina.core.StandardContext.addServletMapping(StandardContext.java:3135)
    at org.apache.catalina.startup.ContextConfig.configureContext(ContextConfig.java:1372)
    at org.apache.catalina.startup.ContextConfig.webConfig(ContextConfig.java:1176)
    at org.apache.catalina.startup.ContextConfig.configureStart(ContextConfig.java:771)
    at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig.java:305)
    at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:95)
    at org.apache.catalina.util.LifecycleBase.fireLifecycleEvent(LifecycleBase.java:90)
    at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5154)
    at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
    ... 6 more

我的web.xml：

<servlet>
    <servlet-name>DispatcherServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
  <servlet-name>dispatcher</servlet-name>
  <url-pattern>*.do</url-pattern>
</servlet-mapping>

Answer 1

<servlet-name>条目的<servlet-mapping>必须与<servlet-name>条目的<servlet>完全相同。

因此，在您的具体情况下，请在<servlet-mapping>条目

中更改此行

<servlet-name>dispatcher</servlet-name>

到

<servlet-name>DispatcherServlet</servlet-name>

Answer 2

如

所述

Caused by: java.lang.IllegalArgumentException: Servlet mapping specifies an unknown servlet name dispatcher

<servlet>和<servlet-mapping>中的servlet名称必须相同。

java.lang.IllegalArgumentException：Servlet映射指定未知的servlet名称

2 个答案: