Question

我有一个gui申请

我将文本放入文本框1，文本框2，............文本框70，然后单击pushButton，
调用return_text ()中的函数module_b.py。现在我可以通过lambda1函数调用一个实例并在class_b中使用它，但是当我点击pushbutton时我无法调用70个实例。

** A-我想在lambda

main.py

** B-我想在(return_text (self, txt))中修改(table2 (self, txt) )和module_b.py以打印并返回值。 student1至student70

任何人都可以帮助我吗？这是代码：

main.py

# -*- coding: utf-8 -*-
from PyQt4 import QtCore, QtGui
import sys
from GUI import Ui_MainWindow
class MainWindow(QtGui.QMainWindow,Ui_MainWindow):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)
        self.ui = Ui_MainWindow()
        self.ui.setupUi(self)
        from module_b import calss_b
        global instance_b
        instance_b=calss_b(self)
        txt1 = self.ui.lineEdit.text #Method reference not Method call
        txt2 = self.ui.lineEdit2.text 
        mySlot = lambda : (instance_b.return_text_username(txt1()) 
        QtCore.QObject.connect(self.ui.pushButton,QtCore.SIGNAL("clicked()"),mySlot)


if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)
    global myapp
    myapp = MainWindow()
    myapp.show()
    sys.exit(app.exec_())

module_b.py

import sys
from GUI import Ui_MainWindow
from PyQt4 import QtCore, QtGui
class calss_b (object):
     def __init__(self, parent=None):
      pass


     def return_text (self, txt):
  ####  global student1, student2 , student3………. Student70
        student1=unicode(txt) 
        return first_student
#####   ….
        …
        return 70

    def table2 (self, txt):
        print student1
        print 2
#####   ….
        …
        print 70

Answer 1

我能做的最好的方法是将所有lineEdit收集到一个列表中并将其传递给return_text方法，然后在每次迭代中调用text()方法，这样：< / p>

number_of_line_Edit = 70
txt = [getattr(self.ui,'lineEdit{0}'.format(i)) for i in range(1,number_of_line_Edit+1)] #This will collect all lineEdit(s) reference so we can call there methods in return_text method
mySlot = lambda :instance_b.return_text(txt)
QtCore.QObject.connect(self.ui.pushButton, QtCore.SIGNAL("clicked()"),  mySlot)

然后使用return_text的{{1}}和table2方法：

module_b.py

请注意，def return_text(self, lineEdit_list): my_text_list = [] for t in lineEdit_list: txt = unicode(t.text()) self.table2(txt) my_text_list.append(txt) #print my_text_list for checking purpose return my_text_list ## I want print password and return it. def table2(self, my_txt): print my_txt列表将始终在每次调用my_text_list方法时重置为空列表，其中它将丢失之前调用的return_text个所有文本。

我无法在一个函数中添加许多值

1 个答案: