Question

我想在数据库中插入实体＆＃34; CategorieTresorerie＆＃34;有两个连接列。问题是，其中一个（RegroupementCategorieTresorerie）试图自动插入...但是这个已经在数据库中，所以我有一个重复的键值违例异常。

错误代码：

Hibernate: insert into "RegroupementCategorieTresorerie" ("RegroupementCategorieTresorerieCode") values (?)
2015-12-29 15:32:05.207  WARN 6960 --- [tomcat-http--26] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 0, SQLState: 23505
2015-12-29 15:32:05.208 ERROR 6960 --- [tomcat-http--26] o.h.engine.jdbc.spi.SqlExceptionHelper   : ERROR: duplicate key value violates unique constraint "RegroupementCategorieTresorerie_PK"
  Détail : Key ("RegroupementCategorieTresorerieCode")=(MARGE_BRUT) already exists.
2015-12-29 15:32:05.210  INFO 6960 --- [tomcat-http--26] o.h.e.j.b.internal.AbstractBatchImpl     : HHH000010: On release of batch it still contained JDBC statements
org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [RegroupementCategorieTresorerie_PK]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement

我要插入的课程：

@Entity
public class CategorieTresorerie
    {
    @Id
    @Column(name="CategorieTresorerieID")
    @SequenceGenerator(name = "CategorieTresorerie_CategorieTresorerieID_seq", sequenceName = "\"CategorieTresorerie_CategorieTresorerieID_seq\"", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "CategorieTresorerie_CategorieTresorerieID_seq")
    private Integer categorieTresorerieId;

    @MapsId
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "regroupementCategorieTresorerieCode", insertable = false, updatable = false)
    @Fetch(FetchMode.JOIN)
    private RegroupementCategorieTresorerie regroupement;

    @MapsId
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "typeCategorieTresorerieId", insertable = false, updatable = false)
    @Fetch(FetchMode.JOIN)
    private TypeCategorieTresorerie typeCategorieTresorerie;

    private Boolean estActif = true;

加入类RegroupementCategorieTresorerie，是hibernate尝试自动插入的那个：

@Entity
public class RegroupementCategorieTresorerie implements EstTraductible
{
    @Id
    private String regroupementCategorieTresorerieCode;

    @Transient
    private String libelle;

加入专栏TypeCategorieTresorerie：

@Entity
public class TypeCategorieTresorerie
    {
    @Id
    @Column(name = "TypeCategorieTresorerieID")
    private Integer typeCategorieTresorerieId;

    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "CategorieTresorerieFamilleID", insertable = false, updatable = false)
    @Fetch(FetchMode.JOIN)
    private CategorieTresorerieFamille famille;

如何在不自动插入连接列的情况下插入CategorieTresorerie？

感谢您的帮助。

Answer 1

不确定在没有看到插入代码的情况下你究竟想要做什么，但是如果你正在尝试加入已经存在的实体，请尝试获取它并指向获取的实体（带有id），这样hibernate就不会尝试创建新记录。

插入带有连接列的实体

1 个答案: