Question

我想在Recycler View中处理事件 -

class RecyclerTouchListener implements RecyclerView.OnItemTouchListener {

        private ClickListener clickListener;
        private GestureDetector gestureDetector;

        public RecyclerTouchListener(Context context, final RecyclerView recyclerView, final ClickListener clickListener){

            this.clickListener = clickListener;
            gestureDetector = new GestureDetector(context, new GestureDetector.SimpleOnGestureListener(){
                @Override
                public boolean onSingleTapUp(MotionEvent e) {
                    return true;
                }

                @Override
                public void onLongPress(MotionEvent e) {
                   View child = recyclerView.findChildViewUnder(e.getX(), e.getY());
                    if(child!=null && clickListener!=null)
                    {
                        clickListener.onLongClick(child, recyclerView.getChildPosition(child));
                        Log.i("TAG", "Radhe handling LongPress ");
                    }
                }
            });
        }

        @Override
        public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {

            View child = rv.findChildViewUnder(e.getX(), e.getY());
            if(child!=null && clickListener!=null && gestureDetector.onTouchEvent(e));
            {
                clickListener.onClick(child, rv.getChildPosition(child));
            }
            return false;
        }

        @Override
        public void onTouchEvent(RecyclerView rv, MotionEvent e) {

        }

        @Override
        public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

        }

    }

    public static interface ClickListener{
        public void onClick(View view, int position);
        public void onLongClick(View view, int position);

    }

此外，我还有以下代码 -

public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        // Inflate the layout for this fragment
        View layout = inflater.inflate(R.layout.fragment_navigation_drawer, container, false);
        recyclerView = (RecyclerView) layout.findViewById(R.id.drawerList);
        filterAdapter = new FilterAdapter(getActivity(), getData());
        recyclerView.setAdapter(filterAdapter);
        recyclerView.setLayoutManager(new LinearLayoutManager(getActivity()));
        recyclerView.addOnItemTouchListener(new RecyclerTouchListener(getActivity(), recyclerView, new ClickListener() {
            @Override
            public void onClick(View view, int position) {
                Log.i("TAG", "Radhe child Clicked ");
                Toast.makeText(getActivity(),"CLick",Toast.LENGTH_SHORT).show();
            }

            @Override
            public void onLongClick(View view, int position) {
                Log.i("TAG", "Radhe child Long Clicked ");
                Toast.makeText(getActivity(),"Long CLick",Toast.LENGTH_SHORT).show();
            }
        }));


        return layout;
    }

现在当我运行它时： - 和

有人能说出为什么会这样吗？我不知道它的原因。提前谢谢。

Answer 1

当您从onClick致电onInterceptTouchEvent时，您需要return true来表明该事件已被消耗，而不是继续为其发起事件。

addOnItemTouchListener的Javadoc说：

一旦监听器从中返回true RecyclerView.OnItemTouchListener.onInterceptTouchEvent（RecyclerView，它的动作 RecyclerView.OnItemTouchListener.onTouchEvent（RecyclerView，将为每个传入的MotionEvent调用MotionEvent方法，直到手势的结束。

和来自onInterceptTouchEvent的错误表示

继续目前的行为并继续观察未来手势中的事件。

只是为了澄清您现有的代码（但是我不确定您尝试使用if语句中的gestureDetector.onTouchEvent（e）实现了什么，请确保您不会意外地使用滚动事件）：

@Override
public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
    View child = rv.findChildViewUnder(e.getX(), e.getY());
    if(child!=null && clickListener!=null && gestureDetector.onTouchEvent(e)) {
        clickListener.onClick(child, rv.getChildPosition(child));
        return true;
    }
    return false;
}

Answer 2

我通常在适配器中处理点击事件，并通过类似下面的界面与片段/活动进行交互。

在适配器的 onBindViewHolder ;

中

viewHolder.mView.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        mListener.onItemClicked(holder.aValue);
    }
});

而mListener是一个带

的界面

public interface IclickListener<T> {

    void onItemClicked(T object);

}

Answer 3

我的解决方案

  public boolean onInterceptTouchEvent(RecyclerView view, MotionEvent e) {
    if(e.getAction()==MotionEvent.ACTION_DOWN) return this.mGestureDetector.onTouchEvent(e);
    View childView = view.findChildViewUnder(e.getX(), e.getY());
    if (childView != null && this.mListener != null && this.mGestureDetector.onTouchEvent(e)) {
        this.mListener.onItemClick(childView, view.getChildAdapterPosition(childView));
        return true;
    }
    return false;

}

Answer 4

我们可以利用Kotlin Extension Functions

用法

myView.setDebounceOnClickListener {
   // your code
}

扩展功能

fun View.setDebounceOnClickListener(onDebounceClick: (View) -> Unit) {
    val debounceClickListener = DebounceClickListener {
        onDebounceClick(it)
    }
    setOnClickListener(debounceClickListener)
}

使用

/**
 * Solves multiple click issue on view
 *
 * @param debounceDelayMillis delay millis which limits the rate at which a function gets invoked
 * @param onDebounceCLick a lambda block which gonna run if the interval between clicks is greater than provided delay millis
 *
 */
class DebounceClickListener(
    private var debounceDelayMillis: Int = 1000,
    private val onDebounceCLick: (View) -> Unit
) : View.OnClickListener {
    private var lastTimeClicked: Long = 0L
    override fun onClick(v: View) {
        if (SystemClock.elapsedRealtime() - lastTimeClicked < debounceDelayMillis) {
            return
        }
        lastTimeClicked = SystemClock.elapsedRealtime()
        onDebounceCLick(v)
    }
}

Answer 5

这应该解决它：

@Override
public boolean onSingleTapUp(MotionEvent e) {
      if(e.getAction()==MotionEvent.ACTION_UP)
      {
            //do something
      }
      return true;
}

Answer 6

我注意到，如果您在recyclerview中有“ n”个项目，它将循环“ n”次。最好只将侦听器放在项目上。但是，

“返回真”使它循环两次。放置一个标志以避免循环（不推荐）

 @Override
            public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
                if(counter[0] ==1) {
                       // code
                    counter[0]=0;
                }
                else counter[0] +=1;

                return true;
            }

在Recyler视图中多次调用onClick

6 个答案: