我正试图从angularJS中获取一个64base编码的字符串,我不太确定我做错了什么。我编写了一个由php运行的makegray.exe写入服务器的映像。现在,我正试图抓取该图像并将其返回到angularJS,然后为用户显示它。这似乎是一个简单的问题,但我对如何做到这一点感到难过。
$scope.MakeGray_Button = function(){
if ($scope.imageUrl) {
var MakeGray_Form = new FormData();
MakeGray_Form.append("FileName", $scope.imageUrl);
$http({
method : "POST",
url : "../opencv/MakeGray/MakeGray.php",
data : MakeGray_Form,
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).
success(function(){
// some magic code here that grabs the $base64 variable from php
})
.error(function(){});
}
else{
alert("Please upload an image");
}
}
PHP
<?php
$imgname = $_POST["FileName"];
$inputDir = "../../uploads/" . $imgname;
$outputDir = "../../processed/" . $imgname;
$MakeGray = "./makegray " . $inputDir . " " . $outputDir;
$runExec = exec($MakeGray, $out);
$type = pathinfo($outputDir, PATHINFO_EXTENSION);
$data = file_get_contents($outputDir);
$base64 = 'data:image/' . $type . ';base64,' . base64_encode($data);
echo "$base64";
?>
答案 0 :(得分:1)
$scope.MakeGray_Button = function(){
if ($scope.imageUrl) {
var MakeGray_Form = new FormData();
MakeGray_Form.append("FileName", $scope.imageUrl);
$http({
method : "POST",
url : "../opencv/MakeGray/MakeGray.php",
data : MakeGray_Form,
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
}).then(function(response){
//response object should hold your base64 image data.
//you can change src of an img tag with ng-src and let the browser render your image.
},function(response){});
}
else{
alert("Please upload an image");
}
}
首先使用.then()
代替已弃用的函数.success()
和.error()
然后也像上面的代码一样捕获response
。
您可以通过将src
标记设为img
来轻松渲染base64图像。 ng-src
应该为此提供帮助。
如果您希望图像为字符串,则应该检查response
对象。
答案 1 :(得分:0)
好的,我让它上班......
=IIf(Fields!cdr_charge_amount.Value < 0.01, "",("Php " & FORMAT(...)))
希望这有助于其他人尝试使用base64编码的字符串从php向JS显示图像!