将来自const u_char *的libpcap数据包数据复制到另一个const u_char *

Question

我正在尝试将const u_char *的深层副本复制到c /++中的另一个const u_char *。

我有以下代码 -

void packetHandler(u_char *userData, const struct pcap_pkthdr* pkthdr, const u_char* packet) 
{
    if(packet!=NULL)
    {
        int length = strlen((char*)packet);
        const u_char* newPacket = new u_char[length];
        memcpy((u_char*)newPacket, packet, length);
        cout<<"Packet - "<<packet<<endl;
        cout<<"New Packet - "<<newPacket<<endl;
        packets.push_back(newPacket);
        //processPacket(packet);
    }
}

但我不认为它被复制得正确，因为2份副本上的操作结果是不同的。

数据必须是const u_char *形式，由pcap循环方法签名决定。

我正在测试更大的[使用tcpdump获得]类型的样本，其中每个数据包是按顺序读取的，我收到一个const u_char *指向它的指针 -

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我要做的是将pcap文件中的所有数据包加载到内存缓冲区中进行高速测试，如果从文件中读取每个数据包，这可能会很慢。

任何指针都会非常感激。

Answer 1

我能够弄明白我的问题。长度不对。我应该使用数据包标题中的长度。无论哪种方式，我觉得使用strlen不是unsigned char的正确选择。

我使用其他帖子vector of packets in libpcap

来计算出来