rails 4上的嵌套资源和简单资源ruby中的多态注释

时间:2015-12-29 07:52:34

标签: ruby-on-rails polymorphism polymorphic-associations

我有以下关系路线:

resources :courses, only: [:index, :show] do
  resources :enrols, only: [:new, :create]
  resources :lectures, only: [:show]
end

resources :code_casts, :path => 'casts', :as => 'casts', only: [:index, :show]
resources :blogs, :path => 'blog', :as => 'blog', only: [:index, :show] do
  resources :blog_votes, only: [:create, :destroy]
end

我想在课程,讲座,code_casts和博客中进行多态评论。

问题是讲座当然有父母,所以路由将是course/course_id/lecture/id,博客路径将blog/id,其中评论将有不同的显示页面。

1 个答案:

答案 0 :(得分:0)

如果我正确理解了问题,那么深层嵌套资源就没什么特别之处了。所以你可能需要这样的东西

# routes.rb
concern :commentable do
  resources :comments
end

resources :courses, only: [:index, :show] do
  resources :enrols, only: [:new, :create]
  resources :lectures, only: [:show], concerns: [:commentable]
end

resources :code_casts, :path => 'casts', :as => 'casts', only: [:index, :show]
resources :blogs, :path => 'blog', :as => 'blog', only: [:index, :show], concerns: [:commentable] do
  resources :blog_votes, only: [:create, :destroy]
end

这将为讲座和博客创建嵌套的comments资源。 您需要区分注释控制器中的路径

# comments_controller
def create
  Comment.create(commentable: commentable, other_params...) # assuming you have `commentable` polymorphic belongs_to
end

# a little more ugly than Ryan suggests
def commentable
  if request.path.include?('blog') # be careful. any path with 'blog' in it will match
    Blog.find(params[:id]) 
  elsif params[:course_id] && request.path.include?('lecture')
    Course.find(params[:course_id).leactures.find(params[:id]) # assuming Course has_many lectures
  else
    fail 'unnable to determine commentable type'
  end
end

所有魔法'是一个可评论的方法,您可以在其中检查路径并确定要选择的可评论对象。我使用类似的方法,但这个确切的代码是由内存编写的,没有测试。希望你有这个想法。