Question

我在MySQL数据库中有2个不同的表（Person和sport）。我想以下列格式从这两个表创建一个json文件。 Person表具有first_name，middle_name和last_name列，sport表具有sport_name和league_name列。从逻辑上讲，每个人可能有多个运动项目。请帮帮我

“score”: {
     “ps”:{
        “person”:{
            “first_name”: "fName1"
            “middle_name”: "MName1"
            “last_name”: "Lname1"               
            "sports":{
                "sport":{
                    “sport_name”: "sport1"
                    “league_name”: "legue1"
                }
                "sport":{
                    “sport_name”: "sport2"  
                    “league_name”: "legue2"
                }
             }
        }
        “person”:{
            .......
        }
    }
}

我绑了以下代码并回答但是我希望将这项运动视为子阵列我尝试了以下代码。我希望运动成为一个人的阵容。

#!/usr/bin/env python
import MySQLdb
import json
import collections
from collections import defaultdict 
class Dict(defaultdict):
    def __init__(self):
        defaultdict.__init__(self, Dict)
    def __repr__(self):
        return dict.__repr__(self) 

db = MySQLdb.connect("Server","userName","pawd","dbName" )

# prepare a cursor object using cursor() method
cursor = db.cursor()
sql = "SELECT person_id,first_name,last_name,gender FROM scorefoliodev1.person "
cursor.execute(sql)

rows = cursor.fetchall()
objects_list = []
for row in rows:
    d = Dict()
    d["Person"]['person_id'] = row[0]
    d["Person"]['first_name'] = row[1]
    d["Person"]['last_name'] = row[2]
    d["Person"]['gender'] = row[3]
    objects_list.append(d)

j = json.dumps(objects_list, indent=4)
print j
objects_file = 'person_info55.js'
f = open(objects_file,'w')
print >> f,j 
db.close()

答案

[
    {
        "Person": {
            "person_id": 111, 
            "gender": "Male", 
            "first_name": "FName1", 
            "last_name": "LName"
        }
    }, 
    {
        "Person": {
            "person_id": 112, 
            "gender": "Male", 
            "first_name": "fname2", 
            "last_name": "lName2"
        }
    }
]

Answer 1

json格式允许您定义数组。你可以这样做：

"sports":[
   {
      "sport_name": "sport1",
      "league_name": "legue1"
   },
   {
      "sport_name": "sport2",
      "league_name": "legue2"
   }
]

Answer 2

我的问题是子数组，运动是人数组的子数组。我是新的到Python并且不知道如何创建列表来生成json文件与子数组

你说：使用＆＃34; person_id＆＃34; 相关的人和运动表。因此，我们可以为人们创建一个包含体育运动的字典。假设e。 G。 SELECT person_id,sport_name,league_name FROM sport生成rows

   [[111, "sport1", "legue1"],
    [112, "sport2", "legue2"],
    [111, "sport3", "legue3"]]

然后我们可以做

sports = {}
for row in rows:
    sport = { "sport_name": row[1], "league_name": row[2] }
    if not row[0] in sports: sports[row[0]] = []
    sports[row[0]].append(sport)

和sports会产生

{
    "112": [ { "league_name": "legue2", "sport_name": "sport2" } ], 
    "111": [ { "league_name": "legue1", "sport_name": "sport1" }, 
             { "league_name": "legue3", "sport_name": "sport3" } ]
}

现在我们有子数组，我们可以简单地将其插入到您已经拥有的人objects_list中：

for person in objects_list:
    person["Person"]['sports'] = sports[person["Person"]['person_id']]

从MySQL DB中的多个表创建Json文件

2 个答案: