Question

我正在尝试使用inlineformset来创建父模型和一些子模型。以下是我的观点。该代码用于将初始Rfq模型保存到数据库，但在尝试保存行inlineformset时出错。这是一对多关系，但是使用ForeignKey字段完成。

# views.py
def rfq_create(request):
    form = RfqForm(request.POST or None)
    RfqFormSet = inlineformset_factory(Rfq, Rfqlines, form=RfqlinesForm, extra=5, can_delete=True)
    lines_formset = RfqFormSet(request.POST or None)
    title = "Create a new RFQ"
    context = {
        "title": title,
        "form": form,
        "lines_formset": lines_formset,
    }

    if form.is_valid() and lines_formset.is_valid():
        rfq = form.save(commit=False)
        rfq.user = request.user
        rfq.save()
        lines_formset.save()
        rfq_list = Rfq.objects.order_by('rfq_id')[:20]
        title = "RFQ List"
        context = {
            "title": title,
            "rfq_list": rfq_list
        }
        return render(request, "rfq.html", context)

    return render(request, "rfq_create.html", context)

我已经尝试过查看官方的Django文档，但它似乎并不适用......或者说不是那么直截了当。

这是我的追溯

Environment:


Request Method: POST
Request URL: http://localhost:8000/rfq/create

Django Version: 1.8.7
Python Version: 3.4.3
Installed Applications:
('django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.sites',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'django.contrib.humanize',
 'django.forms.formsets',
 'jquery',
 'crispy_forms',
 'registration',
 'home',
 'rfq',
 'dashboard',
 'pipeline')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware',
 'django.middleware.security.SecurityMiddleware')


Traceback:
File "/home/brandon/employees/env/lib/python3.4/site-packages/django/core/handlers/base.py" in get_response
  132.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/home/brandon/employees/rfq/views.py" in rfq_create
  36.         lines_formset.save()
File "/home/brandon/employees/env/lib/python3.4/site-packages/django/forms/models.py" in save
  636.         return self.save_existing_objects(commit) + self.save_new_objects(commit)
File "/home/brandon/employees/env/lib/python3.4/site-packages/django/forms/models.py" in save_new_objects
  767.             self.new_objects.append(self.save_new(form, commit=commit))
File "/home/brandon/employees/env/lib/python3.4/site-packages/django/forms/models.py" in save_new
  900.             obj.save()
File "/home/brandon/employees/env/lib/python3.4/site-packages/django/db/models/base.py" in save
  685.                         "unsaved related object '%s'." % field.name

Exception Type: ValueError at /rfq/create
Exception Value: save() prohibited to prevent data loss due to unsaved related object 'rfq'.

Answer 1

问题的答案是这个

lines_formset = RfqFormSet(request.POST or None, instance=form.instance)

form.instance是被忽视的关键。

Answer 2

您需要将父模型实例传递给inline_formset。

有关详细信息，请参阅this relevant section of the Django docs。

示例：

lines_formset = RfqFormSet(request.POST, request.FILES, instance=rfq)

这是必要的，因此Django可以适当地设置子模型的ForeignKey关系。

禁止django save（）以防止由于未保存的相关对象而导致数据丢失

2 个答案: