Question

查询考勤系统的指纹日志几乎没有问题。

我们的示例数据如下所示：

TABLE FINGER_LOGS：

+++++++++++++++++++++++++++++++++++
| ID | FINGER_ID | DATETIME       |
+++++++++++++++++++++++++++++++++++
| 1  | IT         | 2015-12-01 09:00
| 2  | IT         | 2015-12-01 16:30
| 3  | GA         | 2015-12-01 09:30
| 4  | GA         | 2015-12-01 17:00
| 5  | SECURITY   | 2015-12-01 08:00
| 6  | SECURITY   | 2015-12-01 19:00
| 7  | SECURITY2  | 2015-12-01 19:00
| 8  | SECURITy2  | 2015-12-02 07:00

我们必须将TABLE FINGER_LOGS的格式更改为：

++++++++++++++++++++++++++++++++++++++++
| FINGER_ID | DATE       | IN    | OUT |
++++++++++++++++++++++++++++++++++++++++
| IT        | 2015-12-01 | 09:00 | 16:30
| GA        | 2015-12-01 | 09:00 | 17:00
| SECURITY  | 2015-12-01 | 08:00 | 19:00
| SECURITy2 | 2015-12-01 | 19:00 | 07:00    
| SECURITy2 | 2015-12-02 | 19:00 | 07:00

我们尝试过这个查询：

SELECT 
    i.FINGER_ID, i.DATE, i.TIME_IN, o.TIME_OUT
FROM
    (SELECT 
        i.FINGER_ID,
        min(cast(i.DATE as date)) as 'DATE',
        DATE(DATE_ADD(i.DATE, INTERVAL + 1 DAY)) as 'TOMMOROW',     
        min(cast(i.DATE as time)) as 'TIME_IN'
    FROM
        FINGER_LOGS as i
    GROUP BY i.FINGER_ID , cast(i.DATE as date)) as i
        LEFT JOIN
    (SELECT 
        o.FINGER_ID,
            max(cast(o.DATE as date)) as 'DATE',
            max(cast(o.DATE as time)) as 'TIME_OUT'
    FROM
        FINGER_LOGS as o
    GROUP BY o.FINGER_ID , cast(o.DATE as date), DATE(DATE_ADD(o.DATE, INTERVAL - 1 DAY))

    ) as o ON i.FINGER_ID = o.FINGER_ID
        AND (i.DATE = o.DATE
        OR o.DATE = i.TOMMOROW)

但结果是：

++++++++++++++++++++++++++++++++++++++++
| FINGER_ID | DATE       | IN    | OUT |
++++++++++++++++++++++++++++++++++++++++
| IT        | 2015-12-01 | 09:00 | 16:30
| GA        | 2015-12-01 | 09:00 | 17:00
| SECURITY  | 2015-12-01 | 08:00 | 19:00
| SECURITy2 | 2015-12-01 | 19:00 | 19:00    
| SECURITy2 | 2015-12-01 | 19:00 | 07:00
| SECURITy2 | 2015-12-02 | 07:00 | 07:00

问题的根源在DATE IN＆amp;在SECURITy2之外，其具有不同的DATE（从DATE IN开始+1天）

如果您有解决此问题的方法，请告诉我们，

感谢您的帮助和帮助：）

这是来自供应商的必需格式，我来自电子邮件：

....
Our Format :

Database Server  = MySQL
DBName           = ixfinger
Tablename        = fingerlog
Fields :
    Finger_id     autoincrement_primarkey                            
    fingerid      varchar(252) ID from fingerprint
    tdate         date
    timein        time
    timeout       time
    transferred   tinyint (fill with 0)
....

在DATE IN和DATE OUT

0 个答案: