Question

这是代码

include('simple_html_dom.php');
// Create DOM from URL
$page = "http://indonesiax.co.id";
$html = new simple_html_dom();
$html->load_file($page);

// Find all Images
$value = $html->find('div p img', 0)->outerhtml;
echo $value;

我想选择这行代码的outerHTML但不会工作

$value = $html->find('div p img', 0)->outerhtml;

如果你们知道如何在HTML DOM Parser中选择outerHTML，请分享。

抓取的示例页面https://indonesiax.co.id/

我想用这样的标签显示输出完整

<img src="https://files.edx.org/openedx-logos/edx-openedx-logo-tag-dark.png" alt="Powered by Open edX" width="140">

Answer 1

解决。应该是这样的

include('simple_html_dom.php');
// Create DOM from URL
$page = "http://indonesiax.co.id";
$html = new simple_html_dom();
$html->load_file($page);
// Find all images
$altValue = $html->find('div p img', 0);
echo " src= $altValue->src<br /><br />";
echo " alt= $altValue->alt<br /><br />";
echo " width= $altValue->width<br /><br />";

输出就像

src= https://files.edx.org/openedx-logos/edx-openedx-logo-tag-dark.png
alt= Powered by Open edX
width= 140

如何在Simple HTML DOM Parser中选择outerHTML

1 个答案: