Question

我查看了以下几个资源：Remove python dict item from nested json file但似乎无法使我的代码正常工作。根据我对下面的JSON的理解（这是一个WAY较长转储的可变占位符），它是一个带有字典的dict，里面有一个dict，其中随机列出....我最终想看到的是以下打印输出到我的终端：

Message: [Client ID] 
Link: "http://linkgoeshere.com"

这是我到目前为止所拥有的：

ThreeLine= {u'hits': {u'hits': [{u'_id': u'THIS IS THE FIRST ONE',
                  u'_index': u'foo',
                  u'_score': None,
                  u'_source': {u'@timestamp': u'2015-12-21T16:59:40.000-05:00',
                               u'message': u'Application.INFO: [Client ID ] Information Link: http://google.com {"check1":121212} {"tags":{"sent":"15","HTML":"5661"},"person":"15651"}',
                               u'system': u'user-info'}},
                {u'_id': u'THIS IS THE SECOND ONE',
                  u'_index': u'two',
                  u'_score': None,
                  u'_source': {u'@timestamp': u'2015-12-12 T16:59:40.000-05:00',
                               u'message': u'Application.INFO: [Client ID ] Information Link: http://google.com {"check1":565656} {"tags":{"sent":"21","HTML":"4512"},"person":"15651"}',
                               u'system': u'user-info'}},
]}}

unpacking= ThreeLine['hits']['hits'] #we only want to talk to the sort dictionary. 


for d in unpacking:
    newinfo= []
    narrow=[d["_source"] for d in unpacking if "_source" in d] 
    narrower=[d["message"] for d in narrow if "message" in d]
    newinfo.append(narrower)
print newinfo

现在，使用代码原样，它会打印两个条目，但它有很多随意的垃圾，我不关心，就像所有标签一样：

{"tags":{"sent":"21","HTML":"4512"},"person":"15651"}',

那么，我如何进一步删除这些条目，以便我最终想要摆脱这个疯狂嵌套混乱的两条线？如果有人对如何清理当前代码有任何想法，我会全力以赴并准备好学习！

Answer 1

'tags'字典不是字典。它是 text 嵌入在消息字符串中：

>>> ThreeLine['hits']['hits'][0]['_source']['message']
u'Application.INFO: [Client ID ] Information Link: http://google.com {"check1":121212} {"tags":{"sent":"15","HTML":"5661"},"person":"15651"}'

你必须做一些字符串解析来删除它。您可以使用正则表达式：

import re
id_and_link = re.compile(r'(\[[^]]+\]) Information Link: (https?://[\w\d/.]+)')

messages = (entry['_source']['message'] for entry in ThreeLine['hits']['hits'] if '_source' in entry and 'message' in entry['_source'])
for message in messages:
    match = id_and_link.search(message)
    if not match:
        continue
    id_, link = match.groups()
    print 'Message:', id_
    print 'Link:', link
    print

从JSON文件响应中删除Python dict

1 个答案: