Question

我有一个包含文件名的哈希。这些文件名中的每一个都有不同类型的扩展名。即（.txt，.bam，.bam.bai，.fastq等）我试图找出一种迭代这些键并将列表排序为（3）的方法基于HTML / erb中的文件名的三个部分......就像这样。

第1节所有FastQ文件（.fastq）

第2节所有.bam和bam.bai文件（.bam，.bam.bai）

第3节所有文本文件（.txt）

基本上我到目前为止就是这个......

<div class="content_box_title">Sequencing Results</div>
  <div class="content_box">
    <% seqfiles = @vmsr_project.seqfiles %>
    <% seqfiles.keys.sort.each do |file|


      fpath = file.to_s

      fsize = File.size(file)
      fdate = File.mtime(file)
      `enter code here`fsize = fsize / 1000000
      fsize = fsize.to_int
      fsize = fsize.to_s
      if fsize == "0" then fsize = "EMPTY or <1" end
      %>
      <div style="float: left">
        <%= link_to File.basename(file), {:action => "send_analysis_file", :project => @vmsr_project[:proj_id], :file => file }, { :onmouseover => "Tip('<div class=\\'tooltip\\'>Click to download. <p style=\\'color: #e26666;\\'>" + fsize + " MB</p></div>', TITLE, 'Download File')", :onmouseout => "UnTip()" } %>
      </div>
      <div style="float: left">
        &nbsp;(<%= fdate.strftime("%m/%d/%Y") %>):
      </div>
      <div>
        &nbsp;&nbsp;<%= seqfiles[file].join(", ") %>
      </div>
      <div style="clear: both; border-top: 1px solid #ddd;">&nbsp;</div>

        <div style="float: left">
         <!--  <%= fpath %> -->
        </div>


    <% end %>

    <% if seqfiles.empty? %>
      <ul><li>None</li></ul>
    <% end %>

  </div>


  <div class="content_box_title">Aligned</div>
  <div class="content_box">
    <p>.bam, .bam.bai files display here</p>

  </div>

  <div class="content_box_title">QC</div>
  <div class="content_box">
    <p>.txt files display here</p>

  </div>

作为一个更新大家......我得到以下工作（请不要笑，我是新手）但问题现在当然是标题：测序结果每次在所有三个部分中解析时都会打印。绝对需要一个重构。

<% seqfiles.keys.sort.each do |file|

fpath = file.to_s

fsize = File.size(file)
fdate = File.mtime(file)
fsize = fsize / 1000000
fsize = fsize.to_int
fsize = fsize.to_s
if fsize == "0" then fsize = "EMPTY or <1" end

  case fpath
    when /\.fastq.gz$/ %>
      <div class="content_box_title">Sequencing Results</div>
        <div class="content_box">
          <div style="float: left">
            <%= link_to File.basename(file), {:action => "send_analysis_file", :project => @vmsr_project[:proj_id], :file => file }, { :onmouseover => "Tip('<div class=\\'tooltip\\'>Click to download. <p style=\\'color: #e26666;\\'>" + fsize + " MB</p></div>', TITLE, 'Download File')", :onmouseout => "UnTip()" } %>
          </div>
          <div style="float: left">
            &nbsp;(<%= fdate.strftime("%m/%d/%Y") %>):
          </div>
          <div>
            &nbsp;&nbsp;<%= seqfiles[file].join(", ") %>
          </div>
          <div style="clear: both; border-top: 1px solid #ddd;">&nbsp;</div>
        </div>

  <% when /\.bam(\.bai)?$/ %>
      <div class="content_box_title">Aligned</div>
        <div class="content_box">
          <div style="float: left">
            <%= link_to File.basename(file), {:action => "send_analysis_file", :project => @vmsr_project[:proj_id], :file => file }, { :onmouseover => "Tip('<div class=\\'tooltip\\'>Click to download. <p style=\\'color: #e26666;\\'>" + fsize + " MB</p></div>', TITLE, 'Download File')", :onmouseout => "UnTip()" } %>
          </div>
          <div style="float: left">
            &nbsp;(<%= fdate.strftime("%m/%d/%Y") %>):
          </div>
          <div>
            &nbsp;&nbsp;<%= seqfiles[file].join(", ") %>
          </div>
          <div style="clear: both; border-top: 1px solid #ddd;">&nbsp;</div>
        </div>

  <% else %>
      <div class="content_box_title">QC</div>
        <div class="content_box">
          <div style="float: left">
            <%= link_to File.basename(file), {:action => "send_analysis_file", :project => @vmsr_project[:proj_id], :file => file }, { :onmouseover => "Tip('<div class=\\'tooltip\\'>Click to download. <p style=\\'color: #e26666;\\'>" + fsize + " MB</p></div>', TITLE, 'Download File')", :onmouseout => "UnTip()" } %>
          </div>
          <div style="float: left">
            &nbsp;(<%= fdate.strftime("%m/%d/%Y") %>):
          </div>
          <div>
            &nbsp;&nbsp;<%= seqfiles[file].join(", ") %>
          </div>
          <div style="clear: both; border-top: 1px solid #ddd;">&nbsp;</div>
        </div>
  <% end %>
<% end %>

<% if seqfiles.empty? %>
  <ul><li>None</li></ul>
<% end %>

Answer 1

只需将文件名分成3个数组，然后对每个数组进行迭代。

<% separated = seqfiles.keys.sort.inject({}){|h,key|
  case key.to_s
  when /\.fastq$/
    h[:fastq] ||= []
  when /\.bam(\.bai)?$/
    h[:bam] ||= []
  else
    h[:other] ||= []
  end.push(key)
  h
} %>

<% separated[:fastq].each do |file| %>
  ...
<% end %>

<% separated[:bam].each do |file| %>
  ...
<% end %>

<% separated[:other].each do |file| %>
  ...
<% end %>

如何通过文件扩展名对Ruby / Rails中的键/值进行排序？

1 个答案: