Question

我使用以下代码进行多标签数据分类： -

import numpy as np
from sklearn.pipeline import Pipeline
from sklearn.feature_extraction.text import CountVectorizer
from sklearn.svm import LinearSVC
from sklearn.feature_extraction.text import TfidfTransformer
from sklearn.multiclass import OneVsRestClassifier
from sklearn import preprocessing

X_train = np.array(["new york is a hell of a town",
                    "new york was originally dutch",
                    "the big apple is great",
                    "new york is also called the big apple",
                    "nyc is nice",
                    "people abbreviate new york city as nyc",
                    "the capital of great britain is london",
                    "london is in the uk",
                    "london is in england",
                    "london is in great britain",
                    "it rains a lot in london",
                    "london hosts the british museum",
                    "new york is great and so is london",
                    "i like london better than new york"])
y_train_text = [[1],[1],[1],[1],[1],[1],[2],[2],[2],[2],[2],[2],[12],[12]]

X_test = np.array(['nice day in nyc',
                   'welcome to london',
                   'london is rainy',
                   'it is raining in britian',
                   'it is raining in britian and the big apple',
                   'it is raining in britian and nyc',
                   'hello welcome to new york. enjoy it here and london too'])
target_names = ['New York', 'London']

lb = preprocessing.MultiLabelBinarizer()
Y = lb.fit_transform(y_train_text)

classifier = Pipeline([
    ('vectorizer', CountVectorizer()),
    ('tfidf', TfidfTransformer()),
    ('clf', OneVsRestClassifier(LinearSVC()))])

classifier.fit(X_train, Y)
predicted = classifier.predict(X_test)

== OUTPUT =====

[1, 0, 0],'New York'
[0, 1, 0],'London'
[0, 1, 0],'London'
[0, 1, 0],'London'
[1, 0, 0],'New York'
[0, 0, 0], 
[0, 0, 0]]

最后两个是错误的预测，他们应该[0,0,1]为['纽约'，'伦敦']

所以我有这些问题： - 1.]我的代码究竟出了什么问题这是处理“多标签”数据的正确方法吗？或者还有其他更好的方法。因为这和一两个代码都可以在互联网上找到关于“多标签”数据。而二进制分类则有数千种。请帮帮我

Answer 1

12不是“1”而“2”是12，因此

[[1],[1],[1],[1],[1],[1],[2],[2],[2],[2],[2],[2],[12],[12]]

应该是

[[1],[1],[1],[1],[1],[1],[2],[2],[2],[2],[2],[2],[1, 2],[1, 2]]

scikit对多标签数据的问题

1 个答案: