过滤行并消除奇数行

Question

编写复杂查询后，我将列值放入#temp表

            // Complex business logic code
            ...
            ...
             SELECT Distinct
             Jurisdiction,
             JurisdictionX,
             LicenceNumber,
             DateIssued,
             ExpirationDate,
             Resident
             FROM #TEMP

现在它的结果非常接近我的实际解决方案，如图所示......

见上图，其中有6列

如果您注意到有两行具有相同的状态“Alabama”。在一行许可证号中，DateIssued和ExpirationDate列为空。在第二行许可证号中，DateIssued和ExpirationDate列具有值。现在我希望在这种情况下它应该考虑许可证号，DateIssued和ExpirationDate列具有值的第二行，它应该消除许可证号，DateIssued和ExpirationDate列为空的另一行。

任何人都可以帮忙写一下查询吗???

Answer 1

试试这个：

SELECT Distinct Jurisdiction, JurisdictionX, LicenceNumber, DateIssued, ExpirationDate, Resident
FROM #TEMP
WHERE LicenseNumber IS NOT NULL AND 
      DateIssued IS NOT NULL AND 
      ExpirationDate IS NOT NULL
UNION
SELECT Distinct Jurisdiction, JurisdictionX, LicenceNumber, DateIssued, ExpirationDate, Resident
FROM #TEMP
WHERE JurisdictionX NOT IN ( SELECT JurisdictionX from #TEMP
      WHERE LicenseNumber IS NOT NULL AND 
            DateIssued IS NOT NULL AND 
            ExpirationDate IS NOT NULL);