Question

我最近开始在一个新站点上工作，从1.6升级到Django 1.9，并进行了一些更改。我去测试了，这就是我得到的。

Request Method: GET
Request URL: http://example.com/

Django Version: 1.9
Python Version: 2.7.9
Installed Applications:
('django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'mainapp')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware')


Traceback:

File "/var/www/virtualenv-2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  149.                     response = self.process_exception_by_middleware(e, request)

File "/var/www/virtualenv-2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  147.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)

Exception Type: TypeError at /
Exception Value: __init__() takes exactly 1 argument (2 given)

urls.py（尚未完成，但现在已经完成）：

from django.conf.urls import patterns, include, url
from mainapp import views
from django.contrib import admin
admin.autodiscover()

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^u\/[a-zA-Z._0-9]+', views.Index),
    url(r'^', views.Index),

]

Answer 1

你应该为你的项目主页面设置url模式：

url(r'^$', ........)

例如：

url(r'^$',views.Main,name='main')

Django 1.6到1.9：get_response中的/django/core/handlers/base.py

1 个答案: