Question

我正在使用MySQL中的数据库，我有一个表格说ABC。

我想在数据库中查询给定的搜索关键字，并在表格中显示输出。当我使用以下代码查询时，它工作正常:(游戏播放1是列名称）

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM users_entity WHERE `Games Played 1' LIKE '%".$searchword."%'";

但是，当我尝试检查关键字是否出现在两列中时，游戏播放1或游戏播放2 时，它无效。我正在使用以下代码。

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` OR `Games Played 2` LIKE '%".$searchword."%'";

任何人都可以建议我做错了吗？此外，当我使用上面的代码运行网页时，它会发出警告“MySQL服务器已经消失”

Answer 1

if($_POST['searchby'] == "Games Type"){
          $query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` LIKE '%".$searchword."%' OR `Games Played 2` LIKE '%".$searchword."%'";

Answer 2

您的查询应该是这样的：

$query_Recordset1 = "SELECT * FROM elgg_users_entity WHERE `Games Played 1` LIKE '%".$searchword."%' OR `Games Played 2` LIKE '%".$searchword."%'";

Answer 3

<强>错误

错误<div class="form-group"> @Html.LabelFor(model => model.CountyId, htmlAttributes: new { @class = "control-label col-md-2" }) <div class="col-md-10"> @Html.DropDownListFor(model => model.CountyId, new List<SelectListItem> { new SelectListItem {Text = "Alba", Value = "1", Selected = true }, new SelectListItem {Text = "Arad", Value = "2" }, new SelectListItem {Text = "Arges", Value = "3" }, new SelectListItem {Text = "Bacau", Value = "4" }, }, new { @class = "form-control" }) @Html.ValidationMessageFor(model => model.CountyId, "", new { @class = "text-danger" }) </div> </div>条件。

所以最终代码是

WHERE

供您参考

不要在表列名称（if($_POST['searchby'] == "Games Type"){ $query_Recordset1 = " SELECT * FROM elgg_users_entity WHERE table_coumn1 LIKE '%$searchword%' OR table_coumn2 LIKE '%$searchword%' ";）之间使用空格。添加Games Played 1分隔的单词。（Games_Played_1）。

因此，将所有小型上限作为最佳做法

无法从查询MySQL数据库中获得结果

3 个答案:

供您参考