根据style.right重置位置

Question

当图像到达屏幕的最右边时，我是trying to reset animation。

没有这条线，一切都很完美：

if (imgObj.style.right == 0) {
    Reset();
}

  

这不是正确的方法吗？

<!--
var imgObj = null;
var animate;

function init() {
  imgObj = document.getElementById('myImage');
  imgObj.style.position = 'relative';
  imgObj.style.left = '0px';
}

function moveRight() {
  imgObj.style.left = parseInt(imgObj.style.left) + 10 + 'px';
  animate = setTimeout(moveRight, 2000); // call moveRight in 20msec
  if (imgObj.style.right == 0) {
    Reset();
  }
}

function Reset() {
  clearTimeout(animate);
  imgObj.style.left = '0px';
}
window.onload = init;
//-->

<form>
  <img id="myImage" src="http://jsfiddle.net/img/logo.png" />
  <p>Click the buttons below to handle animation</p>
  <input type="button" value="Start" onclick="moveRight();" />
  <input type="button" value="Reset" onclick="reset();" />
</form>

如何让动画与上面的一起工作？

Answer 1

你有一些错误

1. onclick="Reset();"不是onclick="reset();"

2. parseInt(imgObj.style.left.replace("px",""))不是parseInt(imgObj.style.left)

3. imgObj.style.right总是“”你必须设置一些像imgObj.style.left.replace("px","")>200

这样的东西

var imgObj = null;
var animate;

function init() {
  imgObj = document.getElementById('myImage');
  imgObj.style.position = 'relative';
  imgObj.style.left = '0px';
}

function moveRight() {
 
  imgObj.style.left = parseInt(imgObj.style.left.replace("px","")) + 10 + 'px';
  
  animate = setTimeout(moveRight, 2000); // call moveRight in 20msec
 
  if (parseInt(imgObj.style.left.replace("px",""))+ imgObj.width>= window.innerWidth) {
    Reset();
  }
}

function Reset(){

 clearTimeout(animate);
 imgObj.style.left = '0px';
}
window.onload = init;

<form>
  <img id="myImage" src="http://jsfiddle.net/img/logo.png" />
  <p>Click the buttons below to handle animation</p>
  <input type="button" value="Start" onclick="moveRight();" />
  <input type="button" value="Reset" onclick="Reset();return false;" />
</form>