我正在创建一个使用$value = "";
Excel::load(Input::file('excel'), function ($reader) use ($request, &$value) {
$sheets = $reader->get();
foreach($sheets as $sheet) {
$value = $error;
}
}
echo $value;
的应用程序,并使用适用于Android的Volley Networking Library从URL检索JSON数据。
AppController.java
JsonObjectRequest
MainActivity.class中的方法
public class AppController extends AppCompatActivity {
public static final String TAG = AppController.class.getSimpleName();
private RequestQueue mRequestQueue;
private static AppController mInstance;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mInstance = this;
}
public static synchronized AppController getInstance(){
return mInstance;
}
public RequestQueue getRequestQueue(){
if(mRequestQueue == null){
mRequestQueue = Volley.newRequestQueue(getApplicationContext());
}
return mRequestQueue;
}
public <T> void addToRequestQueue(Request<T> req) {
req.setTag(TAG);
getRequestQueue().add(req);
}
}
它出现以下错误:
private void makeJSONObjectRequest() {
showDialog();
JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.GET,
urlJsonObj, (String) null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.d(TAG, response.toString());
try {
//Parsing JSON Object response
String name = response.getString("name");
String email = response.getString("email");
JSONObject phone = response.getJSONObject("phone");
String home = phone.getString("home");
String mobile = phone.getString("mobile");
jsonResponse = "";
jsonResponse += "Name: " + name + "\n\n";
jsonResponse += "Email: " + email + "\n\n";
jsonResponse += "Home: " + home + "\n\n";
jsonResponse += "Mobile: " + mobile + "\n\n";
txtResponse.setTag(jsonResponse);
}
catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_SHORT).show();
}
hideDialog();
}
},
new ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
VolleyLog.d(TAG+"Error:"+ volleyError.getMessage());
Toast.makeText(getApplicationContext(), volleyError.getMessage(), Toast.LENGTH_SHORT).show();
hideDialog();
}
});
/*THE ERROR OCCURS HERE! */
//adding request to the RequestQueue
AppController.getInstance().addToRequestQueue(jsonObjReq);
}
如何纠正此代码?
答案 0 :(得分:7)
您的AppController class
需要扩展Application类而不是AppCompatActivity类。
并记得更新你的清单。即。使用<application>
标记的名称属性在AndroidManifest.xml中添加此类。
<application
android:name=".AppController"/>
答案 1 :(得分:2)
你不能像单身人士一样使用Activity
。 Activity
是您应用的屏幕,在您使用应用期间可能处于不同的状态。你也在泄漏它,因为你保留了它的静态引用。出于您的目的,如果您需要上下文,请扩展Application
而不是AppCompatActivity
,并在您的清单中注册它。
答案 2 :(得分:2)
我认为您应该像这样创建“AppController”:
public class AppController {
private static AppController mInstance;
private RequestQueue mRequestQueue;
private static Context mCtx;
private AppController(Context context){
mCtx = context;
mRequestQueue = getRequestQueue();
}
public static synchronized AppController getInstance(Context context) {
if (mInstance == null) {
mInstance = new AppController(context);
}
return mInstance;
}
public RequestQueue getRequestQueue() {
if (mRequestQueue == null) {
mRequestQueue = Volley.newRequestQueue(mCtx.getApplicationContext());
}
return mRequestQueue;
}
public <T> void addToRequestQueue(@NonNull final Request<T> request) {
getRequestQueue().add(request);
}
public <T> void addToRequestQueueWithTag(@NonNull final Request<T> request, String tag) {
request.setTag(tag);
getRequestQueue().add(request);
}
}
和MainActivity.class
//adding request to the RequestQueue
AppController.getInstance(this).addToRequestQueue(jsonObjReq);
答案 3 :(得分:1)
不要忘记初始化RequestQueue
对象。您需要初始化RequestQueue
方法中的onCreate
,就像您在示例中看到的那样:
(另外,当您致电request.add(jsonObjectRequest)
时,应用程序将尝试引用null
对象)
RequestQueue request;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//request qwe
request= Volley.newRequestQueue(this);
}