我正在使用存储资源存储我的程序找到的基因。这是我正在做的任务。我想确保得到这些结果:
如何使用StorageResource存储我从程序中获取的基因数据?
另外作为旁注,有一个错误,表示无法在for (File f: dr.selectedFiles()){
找到符号。
import edu.duke.FileResource;
import edu.duke.StorageResource;
import edu.duke.DirectoryResource;
public class FindMultiGenes5 {
public int findStopIndex(String dna, int index) {
int stop1 = dna.indexOf("TGA", index);
if (stop1 == -1 || (stop1 - index) % 3 != 0) {
stop1 = dna.length();
}
int stop2 = dna.indexOf("TAA", index);
if (stop2 == -1 || (stop2 - index) % 3 != 0) {
stop2 = dna.length();
}
int stop3 = dna.indexOf("TAG", index);
if (stop3 == -1 || (stop3 - index) % 3 != 0) {
stop3 = dna.length();
}
return Math.min(stop1, Math.min(stop2, stop3));
}
public StorageResource storeAll(String dna) {
//CATGTAATAGATGAATGACTGATAGATATGCTTGTATGCTATGAAAATGTGAAATGACCCAdna = "CATGTAATAGATGAATGACTGATAGATATGCTTGTATGCTATGAAAATGTGAAATGACCCA";
String sequence = dna.toUpperCase();
StorageResource store = new StorageResource();
int index = 0;
while (true) {
index = sequence.indexOf("ATG", index);
if (index == -1)
break;
int stop = findStopIndex(sequence, index + 3);
if (stop != sequence.length()) {
String gene = dna.substring(index, stop + 3);
store.add(gene);
//index = sequence.substring(index, stop + 3).length();
index = stop + 3; // start at the end of the stop codon
}else{ index = index + 3;
}
}
return store;//System.out.println(sequence);
}
public void testStorageFinder() {
DirectoryResource dr = new DirectoryResource();
for (File f: dr.selectedFiles()){
FileResource fr = new FileResource("/Desktop/DNA_Testing/tagfinder2/brca1line.fa");
String dna = fr.asString();
StorageResource s1 = storeAll(dna);
System.out.println("size = " + s1.size());
}
}
public float calCGRatio(String gene){
gene = gene.toUpperCase();
int len = gene.length();
int CGCount = 0;
for(int i=0; i<len; i++){
if(gene.charAt(i) == 'C' || gene.charAt(i) == 'G')
CGCount++;
}//end for loop
System.out.println("CGCount " + CGCount + " Length: " + len + " Ratio: " + (float)CGCount/len);
return (float)CGCount/len;
}//end of calCGRatio() method;
public void printGenes(StorageResource sr){
//create a FindMultiGenesFile object FMG
FindMultiGenes5 FMG = new FindMultiGenes5();
//read a DNA sequence from file
String dna = FMG.readStrFromFile();
//call FMG.findGenes() method to get all genes, and store all genes in an
FMG.findGenes(dna);
//store all genes into a document
StorageResource dnaStore = new StorageResource();
int longerthan60 = 0;
int CGGreaterthan35 = 0;
System.out.println("dnaStore.size: " + dnaStore.size());
System.out.println("\n There are " + dnaStore.size() + " genes. ");
System.out.println("There are " + longerthan60 + " genes longer than 60.");
System.out.println("There are " + CGGreaterthan35 + " genes with CG ratio greater than 0.35.");
}//end main();
}
答案 0 :(得分:0)
错误 - 找不到符号(文件f:dr.selectedFiles()){。是因为你忘了导入java.io. *;
你可以存储这样的基因:
DirectoryResource dr = new DirectoryResource();
StorageResource dnaStore = new StorageResource();
for (File f : dr.selectedFiles()) {
FileResource fr = new FileResource(f);
String s = fr.asString();
dnaStore = storeAll(s);
}
答案 1 :(得分:0)
尝试这样,更容易:
String file = "AAC...(put the dna here).....";
StorageResource genes = storeAll(file);
System.out.println("Number of genes found: " + genes.size());
printGenes(genes);
我认为整个代码不起作用。如果你能妥善解决,请告诉我。