我一直在尝试调试这几个小时,我仍然被卡住了......
我在这段代码中遇到了一个“mkfifo”调用的分段错误(它只是我整个代码的一部分,因为我认为其余部分与此无关):
#include "marketfunc.h"
#include "error.h"
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <signal.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/stat.h>
#define PIPE_PATH "./pipe.fifo"
struct myStruct
{
int x;
int y;
int z;
};
struct myStruct *s;
int main(int argc, char **argv)
{
s = malloc(sizeof(struct myStruct));
// 'int marketfunc_init(int x)' is defined in a perfectly working extern library
if(marketfunc_init(1) == -1) error("failed to initialize marketfunc library", 5);
printf("test1\n");
// Segmentation fault
if(mkfifo(PIPE_PATH, 0666) == -1) error("failed to create pipe", 1);
printf("test2\n");
//...
}
产生此输出(executableFile是我文件的名称):
test1
bin/executableFile: Segmentation fault (core dumped)
gdb backtrace产生了这个:
#0 strchrnul () at ../sysdeps/x86_64/strchr.S:32
#1 0x00007ffff7a5ed82 in __find_specmb (format=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>)
at printf-parse.h:108
#2 _IO_vfprintf_internal (s=0x7fffffffb5a0, format=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>,
ap=0x7fffffffdd58) at vfprintf.c:1332
#3 0x00007ffff7a63f31 in buffered_vfprintf (s=s@entry=0x7ffff7dd41c0 <_IO_2_1_stderr_>,
format=format@entry=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>, args=args@entry=0x7fffffffdd58)
at vfprintf.c:2356
#4 0x00007ffff7a5eeae in _IO_vfprintf_internal (s=0x7ffff7dd41c0 <_IO_2_1_stderr_>,
format=format@entry=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>, ap=ap@entry=0x7fffffffdd58)
at vfprintf.c:1313
#5 0x00007ffff7b0c595 in error_tail (status=status@entry=4199947, errnum=errnum@entry=1,
message=message@entry=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>, args=args@entry=0x7fffffffdd58)
at error.c:201
#6 0x00007ffff7b0c6ed in __error (status=4199947, errnum=1,
message=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>) at error.c:251
#7 0x0000000000400b78 in main (argc=1, argv=0x7fffffffdf38) at src/executableFile.c:75
虽然创建了“pipe.fifo”文件... 在此先感谢您的帮助!
编辑:
错误在error.c中简单定义,并且在error.h中是签名:
#include "error.h"
#include <stdlib.h>
#include <stdio.h>
void error(char *msg, int ret)
{
perror(msg);
exit(ret);
}
答案 0 :(得分:0)
如果查看堆栈跟踪,您会看到对error()
的调用显示为:
0x00007ffff7b0c6ed in __error (status=4199947, errnum=1, message=0xffffffffffffff60 <error: Cannot access memory at address 0xffffffffffffff60>) at error.c:251
这是 NOT 您定义的error()
函数。相反,它是error()
中定义的error.h
函数,具有以下签名:
void error(int status, int errnum, const char *format, ...);
请参阅error.h。
正如您所看到的,此函数需要char* format
作为最后一个参数,它会从堆栈0xffffffffffffff60
中获取一些垃圾,因为您根本不传递第三个参数。似乎链接器正在解析对error()
的错误函数的调用。
作为快速修复,我会按如下方式重命名:
rename your file `error.h` to `error_my.h`
your definition of `error()` to, say, `error_my()`
replace the calls to `error()` with `error_my()`.
您的代码如下:
#include "marketfunc.h"
#include "error_my.h" // <=======================
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <signal.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/stat.h>
#define PIPE_PATH "./pipe.fifo"
struct myStruct
{
int x;
int y;
int z;
};
struct myStruct *s;
int main(int argc, char **argv)
{
s = malloc(sizeof(struct myStruct));
// 'int marketfunc_init(int x)' is defined in a perfectly working extern library
if(marketfunc_init(1) == -1) error_my("failed to initialize marketfunc library", 5); // <=======================
printf("test1\n");
// Segmentation fault
if(mkfifo(PIPE_PATH, 0666) == -1) error_my("failed to create pipe", 1); // <=======================
printf("test2\n");
//...
}
errno
在mkfifo()
未能找到失败的原因时打印<%= form_tag img_upload_create_path, method: "POST", html: { multipart: true }
。