geom_text（）具有重叠标签

Question

因此我的散点图的一些标签重叠。我已尝试将direct.label与方法＆＃34; smart.grid＆＃34;一起使用，但它不会产生适当的结果。这是我目前的图表：

生成它的代码：

ggplot(d, aes(x=ILE2, y=TE,label=d$CA)) +
  geom_point(mapping=aes(x=ILE2, y=TE, fill=d$CA), size=9, shape=20, color="black") +
  geom_text(data = d,mapping=aes(x=ILE2, y=TE,label=d$CA), size=4, vjust=3, hjust=0.5,size=6)+
  geom_smooth(method=lm,se=F)+
  theme(legend.position = "none")+
  ggtitle("Tasa de Empleo según Índice de Libertad Económica") +
  labs(x="Índice de Libertad Económica",y="Tasa de Empleo") + 
  theme(plot.title = element_text(family =windowsFonts(Times=windowsFont("TT Times New Roman")), color="#666666", face="bold", size=22, hjust=0.5)) +
  theme(axis.title = element_text(family =windowsFonts(Times=windowsFont("TT Times New Roman")), color="#666666", face="bold", size=22)) 

数据：

structure(list(CA = structure(c(1L, 2L, 3L, 4L, 6L, 8L, 9L, 5L, 
7L, 10L, 11L, 12L, 14L, 15L, 16L, 17L, 13L), .Label = c("Andalucía", 
"Aragón", "Asturias", "Balears", "C. La Mancha", "C. Valenciana", 
"C. y León", "Canarias", "Cantabria", "Cataluña", "Extremadura", 
"Galicia", "La Rioja", "Madrid", "Murcia", "Navarra", "País Vasco"
), class = "factor"), CA.excel = structure(c(1L, 2L, 3L, 4L, 
10L, 5L, 6L, 7L, 8L, 9L, 11L, 12L, 13L, 14L, 15L, 16L, 17L), .Label = c("Andalucía", 
"Aragón", "Asturias, Principado de", "Balears, Illes", "Canarias", 
"Cantabria", "Castilla - La Mancha", "Castilla y León", "Cataluña", 
"Comunitat Valenciana", "Extremadura", "Galicia", "Madrid, Comunidad de", 
"Murcia, Región de", "Navarra, Comunidad Foral de", "País Vasco", 
"Rioja, La"), class = "factor"), ILE = c(0.64, 0.45, 0.61, 0.36, 
0.4, 0.4, 0.48, 0.54, 0.5, 0.5, 0.72, 0.53, 0.19, 0.49, 0.43, 
0.46, 0.39), ILE2 = c(0.36, 0.55, 0.39, 0.64, 0.6, 0.6, 0.52, 
0.46, 0.5, 0.5, 0.28, 0.48, 0.81, 0.51, 0.58, 0.54, 0.61), TE = c(39.04, 
47.6, 40.61, 48.82, 44.65, 43.06, 45.77, 41.85, 43.49, 49.76, 
38.38, 41.82, 53.08, 43.4, 49.49, 47.98, 48.83), migdest = c(21774L, 
5511L, 3147L, 9333L, 17187L, 7568L, 2689L, 12547L, 8701L, 19727L, 
3878L, 6147L, 38182L, 6678L, 3024L, 7363L, 1736L), Poblacion = c(8399618L, 
1326403L, 1049875L, 1124972L, 4939674L, 2126144L, 585359L, 2062767L, 
2478079L, 7396991L, 1091623L, 2734656L, 6385298L, 1463773L, 636402L, 
2165100L, 313569L), MigraPob = c(0.002592261, 0.004154845, 0.002997501, 
0.008296203, 0.003479379, 0.003559496, 0.004593765, 0.006082607, 
0.003511188, 0.002666895, 0.003552507, 0.002247815, 0.005979674, 
0.004562182, 0.004751713, 0.003400767, 0.005536262), Ocupados = structure(c(3L, 
12L, 9L, 10L, 1L, 14L, 5L, 13L, 16L, 7L, 8L, 17L, 4L, 11L, 6L, 
15L, 2L), .Label = c("1.836.300", "126.900", "2.683.700", "2.786.600", 
"226.300", "258.200", "3.023.200", "350.100", "371.800", "455.900", 
"513.400", "524.500", "707.000", "771.500", "870.300", "913.300", 
"987.500"), class = "factor"), Activos = structure(c(11L, 15L, 
12L, 14L, 6L, 2L, 7L, 17L, 3L, 9L, 13L, 4L, 8L, 16L, 10L, 1L, 
5L), .Label = c("1.041.500,00", "1.115.000,00", "1.147.000,00", 
"1.263.200,00", "153.900,00", "2.425.100,00", "277.900,00", "3.389.400,00", 
"3.781.300,00", "306.100,00", "4.042.900,00", "458.900,00", "501.800,00", 
"586.600,00", "644.300,00", "700.300,00", "991.500,00"), class = "factor"), 
    Tocup = c(0.664, 0.814, 0.81, 0.777, 0.757, 0.692, 0.814, 
    0.713, 0.796, 0.8, 0.698, 0.782, 0.822, 0.733, 0.844, 0.836, 
    0.825), Paro = c(0.336, 0.186, 0.19, 0.223, 0.243, 0.308, 
    0.186, 0.287, 0.204, 0.2, 0.302, 0.218, 0.178, 0.267, 0.156, 
    0.164, 0.175), X..Emp.disueltas14 = structure(c(9L, 16L, 
    12L, 15L, 17L, 8L, 14L, 1L, 7L, 4L, 11L, 2L, 13L, 10L, 5L, 
    3L, 6L), .Label = c("1.102", "1.529", "1.544", "1.953", "160", 
    "196", "2.465", "260", "3.172", "349", "362", "467", "5.147", 
    "552", "833", "846", "915"), class = "factor"), EmpD1000h = c(0.3776, 
    0.6378, 0.4448, 0.7405, 0.1852, 0.1223, 0.943, 0.5342, 0.9947, 
    0.264, 0.3316, 0.5591, 0.8061, 0.2384, 0.2514, 0.7131, 0.6251
    ), EmpCreadas = c(15541L, 1933L, 1364L, 2887L, 11206L, 3486L, 
    819L, 2812L, 3000L, 17664L, 1186L, 4266L, 20268L, 2732L, 
    905L, 3447L, 448L), TasaEmpC = c(1.850203188, 1.45732481, 
    1.299202286, 2.566286094, 2.26857076, 1.639587911, 1.399141382, 
    1.363217465, 1.210615158, 2.387998039, 1.086455672, 1.559976831, 
    3.174166656, 1.866409614, 1.422057127, 1.592074269, 1.42871266
    ), RentaMediaHogar = c(21332L, 29120L, 25623L, 26923L, 22392L, 
    21539L, 23905L, 22271L, 24587L, 30407L, 19364L, 26001L, 31587L, 
    21269L, 33047L, 34240L, 26666L), GananciaMediaTrab = c(20782.03, 
    22054.85, 21994.99, 20776.29, 19167.93, 20052.12, 20440.56, 
    20630.07, 24253.73, 20878.02, 19129.72, 19824.66, 26215.36, 
    20449.83, 23836.93, 26915.07, 20628.81)), .Names = c("CA", 
"CA.excel", "ILE", "ILE2", "TE", "migdest", "Poblacion", "MigraPob", 
"Ocupados", "Activos", "Tocup", "Paro", "X..Emp.disueltas14", 
"EmpD1000h", "EmpCreadas", "TasaEmpC", "RentaMediaHogar", "GananciaMediaTrab"
), class = "data.frame", row.names = c(NA, -17L))

Answer 1

我认为您可以采用多种策略，这取决于您是需要通用解决方案还是仅需要针对此特定图表的解决方案。

首先，您可以使用我在上面链接的问题中描述的偏移或抖动作为可能的重复。 IE-here。这可能提供了最通用的解决方案。

但是，如果您只需要针对此特定图表使用此功能，则可以对多个public static void main(String[] args) { valueHolder values = sortFile(args[0]); // this returns 3 variables, nWords, nSyllables, nSentences getFRE(values); // these "cannot be resolved to a variable" } 调用使用重叠的标签（数据中只有少数几个），我们使用不同的偏移量geom_text ，hjust），用于每个标签集。

vjust

显然，您可以根据自己的需要调整hjust / vjust，以使标签更清晰。 注意：我收到有关没有特定字体系列的警告。如果您提供字体库，我可以更新解决方案。

Answer 2

您可以考虑尝试ggrepel放置标签而不重叠。

library(ggrepel)
ggplot(d, aes(x=ILE2, y=TE,label=d$CA)) +
  geom_point(mapping=aes(x=ILE2, y=TE, fill=d$CA), size=9, shape=20, color="black") +
  geom_text_repel(
    data = d,
    mapping=aes(x=ILE2, y=TE,label=d$CA),
    size=4, size=6, box.padding = unit(0.5, "lines")
  )+
  geom_smooth(method=lm,se=F)+
  theme(legend.position = "none")+
  ggtitle("Tasa de Empleo según Índice de Libertad Económica") +
  labs(x="Índice de Libertad Económica",y="Tasa de Empleo")