Question

我有2张桌子

table_orders - order_id, customer_id;
table_order_details - order_id, product_sell_price, quantity;

我想获得每个订单的订单价值（金额总和）。我正在尝试这个查询：

mysql> select O.order_id, sum(OD.product_sell_price * OD.quantity) from table_order_details as OD INNER JOIN table_orders as O where O.order_id = TOD.order_id;

但是它给出了总和，即所有订单的总和。

如何获取每个订单的订单价值？

有人可以帮我吗？

Answer 1

最后添加GROUP BY

SELECT O.order_id, SUM(OD.product_sell_price * OD.quantity) 
FROM table_order_details as OD 
INNER JOIN table_orders as O 
ON O.order_id = OD.order_id
 GROUP BY  O.order_id

Answer 2

您只需使用 GROUP BY 子句按顺序获取 SUM

试试这个：

SELECT O.order_id, SUM(OD.product_sell_price * OD.quantity) 
FROM table_order_details AS OD 
INNER JOIN table_orders AS O WHERE O.order_id = OD.order_id
GROUP BY O.order_id;

函数SUM在MYSQL中未按预期工作

2 个答案: