Question

我希望根据选定的TIMESTAMP获取STRING_VALUE和ID的值。假设我的选定ID为4259,4226且4259 然后，应使用CASE语句为所选TIMESTAMP选择STRING_VALUE和ID。我尝试了下面的查询，但返回错误

CREATE TABLE "DRL_FTO3_DI1_A0"
(
  "VARIABLE" integer,
  "CALCULATION" integer,
  "TIMESTAMP_S" integer,
  "TIMESTAMP_MS" integer,
  "VALUE" double precision,
  "STATUS" integer,
  "GUID" character(36),
  "STRVALUE" character varying(50)
)

INSERT INTO "DRL_FTO3_DI1_A0"(
            "VARIABLE", "CALCULATION", "TIMESTAMP_S", "TIMESTAMP_MS", "VALUE", 
            "STATUS", "GUID", "STRVALUE")
    VALUES (4226, 0, 1451120925, 329,0 , 1078067200, '', 'BATCH 1'),
           (4306, 0, 1451120925, 329,0 , 1078067200, '', 'BATCH 2'),
           (4311, 0, 1451120925, 329,0 , 1078067200, '', '2')

现在假设有三个变量（4226,4306,4311）我想选择4226和4311

SELECT ((TIMESTAMP WITHOUT Time Zone 'epoch' + "TIMESTAMP_S" * INTERVAL '1 second') AT TIME ZONE 'UTC')::TIMESTAMP WITHOUT Time Zone,
SUM(CASE WHEN "VARIABLE" = 4226 Then "STRVALUE" END) as 'A',
SUM(CASE WHEN "VARIABLE" = 4311 Then "STRVALUE" END) as 'B'
FROM "DRL_FTO3_DI1_A0"
GROUP BY "TIMESTAMP_S"
ORDER BY "TIMESTAMP_S";


 TIMESTAMP_S                         A            B
 2015-12-26 14:38:45                BATCH_1       2

选择基于Postgres中的列值

0 个答案: