Question

我很难从以下字符串中提取纬度和经度子字符串+ 25.1870 + 055.2784 /

由于这是一个位置字符串，+符号可能是 - 。我正在寻找一种能够识别+或 - 符号的方法，并在第二个+ / - 符号的开头创建第一个字符串，在第二个字符串中创建第二个字符串。

我在下面发布了我的方法。它完美无缺，但我觉得它有点复杂。

NSString *itemValue = [NSString stringWithFormat:@"%@",item.value];
        NSLog(@"ITEM VALUE = %@", itemValue);

        NSString *firstSign = [itemValue substringToIndex:1];
        NSLog(@"FIRST SIGN = %@", firstSign);

        NSString *stringExcludingFirstSign = [itemValue substringWithRange:NSMakeRange(1, itemValue.length - 1)];

        NSLog(@"STRING EXCLUDING FIRST SIGN = %@", stringExcludingFirstSign);

        NSString *latitudeWithoutSign;

        NSScanner *scanner = [NSScanner scannerWithString:stringExcludingFirstSign];

        if([stringExcludingFirstSign containsString:@"+"]){
            [scanner scanUpToString:@"+" intoString:&latitudeWithoutSign];
        }
        else if([stringExcludingFirstSign containsString:@"-"]){
            [scanner scanUpToString:@"-" intoString:&latitudeWithoutSign];
        }

        NSLog(@"LATITUDE WITHOUT SIGN = %@", latitudeWithoutSign);

        NSString *latitude = [NSString stringWithFormat:@"%@%@", firstSign, latitudeWithoutSign];

        NSLog(@"LATITUDE = %@", latitude);

        NSString *longitude = [itemValue substringWithRange:NSMakeRange(scanner.scanLocation + 1, (itemValue.length - (scanner.scanLocation + 1)) - 1)];

        NSLog(@"LONGITUDE = %@", longitude);

Answer 1

你的字符串的问题在于你没有任何类型的分隔符可以指示纬度/经度的位置。所以这就是我如何处理这个问题。

您需要做的是首先从字符串中删除反斜杠。它没有用处
接下来将所有+或 - 替换为前面的空格
由于字符串最前面会有空格，您需要删除
一旦完成，你现在使用由字符串功能分隔的组件来分离你的长＆amp; LAT。
lat和long在数组中。得到他们并随心所欲地做任何事情

这是我已经测试过的工作代码

NSString *myCordStr = @"+25.1870+055.2784/";
    myCordStr=[myCordStr stringByReplacingOccurrencesOfString:@"/" withString:@""];
    myCordStr=[myCordStr stringByReplacingOccurrencesOfString:@"-" withString:@" -"];
    myCordStr=[myCordStr stringByReplacingOccurrencesOfString:@"+" withString:@" +"];

    NSString *newCordStr = [myCordStr substringFromIndex:1];

    NSLog(@"myCordStr:%@ ...", myCordStr);
    NSLog(@"newCordStr:%@ ...", newCordStr);

    NSArray *coordArray = [newCordStr componentsSeparatedByString:@" "];
    NSLog(@"coordArray: %@ ...", coordArray);

OUTPUT:
myCordStr: +25.1870 +055.2784 ...
newCordStr:+25.1870 +055.2784 ...
coordArray: (
    "+25.1870",
    "+055.2784"
) ...

Answer 2

虽然它有点复杂，但下面的代码可以解决问题。

NSString * itemValue = [NSString stringWithFormat：@＆＃34;％@＆＃34;，item.value]; NSLog（@＆＃34; ITEM VALUE =％@＆＃34;，itemValue）;

    NSString *firstSign = [itemValue substringToIndex:1];
    NSLog(@"FIRST SIGN = %@", firstSign);

    NSString *stringExcludingFirstSign = [itemValue substringWithRange:NSMakeRange(1, itemValue.length - 1)];

    NSLog(@"STRING EXCLUDING FIRST SIGN = %@", stringExcludingFirstSign);

    NSString *latitudeWithoutSign;

    NSScanner *scanner = [NSScanner scannerWithString:stringExcludingFirstSign];

    if([stringExcludingFirstSign containsString:@"+"]){
        [scanner scanUpToString:@"+" intoString:&latitudeWithoutSign];
    }
    else if([stringExcludingFirstSign containsString:@"-"]){
        [scanner scanUpToString:@"-" intoString:&latitudeWithoutSign];
    }

    NSLog(@"LATITUDE WITHOUT SIGN = %@", latitudeWithoutSign);

    NSString *latitude = [NSString stringWithFormat:@"%@%@", firstSign, latitudeWithoutSign];

    NSLog(@"LATITUDE = %@", latitude);

    NSString *longitude = [itemValue substringWithRange:NSMakeRange(scanner.scanLocation + 1, (itemValue.length - (scanner.scanLocation + 1)) - 1)];

    NSLog(@"LONGITUDE = %@", longitude);

Answer 3

您可以使用NSRegularExpression，然后使用matchesInString:options:range获取两个坐标的数组。

正则表达式为(+|-)\d+\.\d+

完整代码：

NSString *string = @"+25.1870+055.2784"
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"(+|-)\d+\.\d+" options:nil error:nil]
NSArray *result = [regex matchesInString:string options:nil range:NSMakeRange(0, string.length)]

从以下字符串+ 25.1870 + 055.2784 /中提取纬度和经度子字符串

3 个答案: