我在目标C中有两个数组。他们的数据结构如下:
{"index":"1","lastName":"Brown","firstName":"Kathy","company":"ABC inc."},
{"index":"2","lastName":"Smith","firstName":"Mike","company":"XYZ inc."}
和
{"index":"1","make":"Toyota","model":"RAV4","year":"2009"},
{"index":"2","make":"Honda","model":"Pilot","year":"2012"}
我的任务是将这两个数组放入一个json NSData对象中。同时,在json数据中,我应该将名称“People”分配给第一类数组实体,将“Car”分配给第二类数组实体,所以稍后在php端,我应该能够分辨出哪个是哪个并将它们分别放入不同的表中。你能帮我找到生成所需json对象的正确方法吗?
答案 0 :(得分:3)
您可以使用两个数组people
和cars
构建一个包含两个数组的新字典,使用两个数组作为与这两个键关联的值。例如:
NSArray *people = @[@{@"index":@"1",@"lastName":@"Brown",@"firstName":@"Kathy",@"company":@"ABC inc."},
@{@"index":@"2",@"lastName":@"Smith",@"firstName":@"Mike",@"company":@"XYZ inc."}];
NSArray *cars = @[@{@"index":@"1",@"make":@"Toyota",@"model":@"RAV4",@"year":@"2009"},
@{@"index":@"2",@"make":@"Honda",@"model":@"Pilot",@"year":@"2012"}];
NSDictionary *fullDictionary = @{@"people": people, @"cars": cars};
NSError *error;
NSData *data = [NSJSONSerialization dataWithJSONObject:fullDictionary options:0 error:&error];
生成的JSON(格式化以便您可以更轻松地阅读)看起来像:
{
"cars" : [
{
"model" : "RAV4",
"year" : "2009",
"make" : "Toyota",
"index" : "1"
},
{
"model" : "Pilot",
"year" : "2012",
"make" : "Honda",
"index" : "2"
}
],
"people" : [
{
"lastName" : "Brown",
"firstName" : "Kathy",
"company" : "ABC inc.",
"index" : "1"
},
{
"lastName" : "Smith",
"firstName" : "Mike",
"company" : "XYZ inc.",
"index" : "2"
}
]
}
要发送该请求,您可以执行以下操作:
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
request.HTTPBody = data;
request.HTTPMethod = @"POST";
NSURLSessionTask *task = [[NSURLSession sharedSession] dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// check for fundamental networking error (e.g. not connected to Internet)
if (error) {
NSLog(@"error = %@", error);
return;
}
// also check to see if the server reported some HTTP error
if ([response isKindOfClass:[NSHTTPURLResponse class]]) {
NSInteger statusCode = [(NSHTTPURLResponse *)response statusCode];
if (statusCode != 200) {
NSLog(@"statusCode = %ld", (long)statusCode);
return;
}
}
// OK, if we've gotten here, let's parse the response; I'm assuming you'll send JSON response; so parse it
NSError *parseError;
NSDictionary *responseObject = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
if (parseError) {
NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"responseString = %@", responseString);
} else {
NSLog(@"responseObject = %@", responseObject);
}
}];
[task resume];
在PHP中,要解析此响应,您可以执行以下操作:
<?php
header("Content-Type: application/json");
$handle = fopen("php://input", "rb");
$raw_post_data = '';
while (!feof($handle)) {
$raw_post_data .= fread($handle, 8192);
}
fclose($handle);
$json_data = json_decode($raw_post_data, true);
$people = $json_data["people"];
$cars = $json_data["cars"];
foreach ($people as $person) {
$index = $person["index"];
$last_name = $person["lastName"];
$first_name = $person["firstName"];
$company = $person["company"];
// use these four variables to insert row of data here; note, make sure you either use
// `mysqli::real_escape_string` or that you manually bind these values to `?` placeholders
}
foreach ($cars as $car) {
$index = $car["index"];
$make = $car["make"];
$model = $car["model"];
$year = $car["year"];
// again, use these four variables to insert row of data here; note, make sure you either use
// `mysqli::real_escape_string` or that you manually bind these values to `?` placeholders
}
// obviously, if we had errors above, we'd send something like Array("success" => false, ...) with error messages and error codes
$response = Array("success" => true);
echo json_encode($response);
?>
答案 1 :(得分:0)
在PHP中,您可以组合2个jsons,如下所示
$j1 = '[{"index":"1","lastName":"Brown","firstName":"Kathy","company":"ABC inc."},
{"index":"2","lastName":"Smith","firstName":"Mike","company":"XYZ inc."}]';
$j2 = '[{"index":"1","make":"Toyota","model":"RAV4","year":"2009"},
{"index":"2","make":"Honda","model":"Pilot","year":"2012"}]';
$combined_array = array("People"=>json_decode($j1, true)) + array("Cars"=>json_decode($j2, true));
$combined_json = json_encode($combined_array);
print_r($combined_array);
print_r($combined_json);
输出:
Array
(
[Peolpe] => Array
(
[0] => Array
(
[index] => 1
[lastName] => Brown
[firstName] => Kathy
[company] => ABC inc.
)
[1] => Array
(
[index] => 2
[lastName] => Smith
[firstName] => Mike
[company] => XYZ inc.
)
)
[Cars] => Array
(
[0] => Array
(
[index] => 1
[make] => Toyota
[model] => RAV4
[year] => 2009
)
[1] => Array
(
[index] => 2
[make] => Honda
[model] => Pilot
[year] => 2012
)
)
)
{"Peolpe":[{"index":"1","lastName":"Brown","firstName":"Kathy","company":"ABC inc."},
{"index":"2","lastName":"Smith","firstName":"Mike","company":"XYZ inc."}],
"Cars":[{"index":"1","make":"Toyota","model":"RAV4","year":"2009"},
{"index":"2","make":"Honda","model":"Pilot","year":"2012"}]}
如果要打印json字符串的输出,可以使用json_encode的JSON_PRETTY_PRINT
选项
$combined_json = json_encode($combined_array, JSON_PRETTY_PRINT);