我想在node.js中使用sequqlize在另一个查询之后进行查询。第二个查询迭代第一个元素查询结果。
代码:
exports.index = function(req, res) {
sqldb.sequelize.query("select * from food", {type: sqldb.sequelize.QueryTypes.SELECT})
.then(function (food) {
for (var i = food.length; i--;) {
sqldb.sequelize.query("select i.name_ingredient " +
"from food_incredients as fi, " +
"ingredients as i " +
"where fi.food_id = " + food[i].id + " and " +
"i.id = fi.ingredient_id;",
{type: sqldb.sequelize.QueryTypes.SELECT}).then(function (ingredients) {
food[i]["ingredients"] = ingredients;
});
}
res.status(200).json(food);
}
);
当我尝试添加" infredients"我发现了一个错误,即食物[i]"对象未定义。我怎样才能解决这个问题并返回"食物"每种元素的成分?
由于