Question

我正在编写一个程序来为一种语言生成单词。这是我的代码：

def correct(list)
    unless @vowel
        filter_consonants(list)
        similarity_avoidance(list)
    end
    puts "Corrected list: " + list
    return list
end

def similarity_avoidance(list)
    puts list.size
    sublist = ""
    subsublist = ""
    list.each_char do |character|
        sublist += character if similarity_exists?(character, @root)
    end
    sublist.each_char do |character|
        subsublist += character if @root.include?(character)
    end
    sublist.each_char do |character|
        sublist.delete!(character) if subsublist.include?(character)
    end
    sublist += subsublist
    list.each_char do |character|
        list.delete!(character) if sublist.include?(character)
    end
    list += sublist
    puts "Corrected for similarity: " + list
end

当函数更改了一串字符时，字符串中的某些字符就会消失。我不知道我做错了什么或不管我是谁。有谁知道什么？

Answer 1

您没有将传递给函数的字符串对象的值更改为参数list。你正在做的是在函数体内为list分配一个不同的字符串对象。 list不是对象，它是对一个或另一个对象的引用 - 函数参数列表中的list与外部list不同的引用功能。重命名参数，澄清问题会很有帮助。

您需要做的是将内部价值提供给外部。在函数中执行此操作的机制是return语句。

尝试从函数返回（inside）list的新值，并在调用函数时将函数返回值分配给外部list。

同样的逻辑适用于您尝试更改list值的两个函数。您还需要在list结束时返回filter_consonants。

def correct(list)
    unless @vowel
        list = filter_consonants(list)
        list = similarity_avoidance(list)
    end
    puts "Corrected list: " + list
    return list
end

def similarity_avoidance(list)
    puts list.size
    sublist = ""
    subsublist = ""
    list.each_char do |character|
        sublist += character if similarity_exists?(character, @root)
    end
    sublist.each_char do |character|
        subsublist += character if @root.include?(character)
    end
    sublist.each_char do |character|
        sublist.delete!(character) if subsublist.include?(character)
    end
    sublist += subsublist
    list.each_char do |character|
        list.delete!(character) if sublist.include?(character)
    end
    list += sublist
    puts "Corrected for similarity: " + list
    return list
end

字符在函数结束时消失

1 个答案: