Question

我必须执行一个移动平均线。在下面的代码中，输入文件（stress1.txt）包含两列x和y值。每个y介于0.9x和1.1x之间需要进行平均。遍及这两个列表的代码的最后一部分是正确的，因为它在我打印出来时为每个上限和下限返回正确的x值。但是，平均值没有正确完成，我已经尝试了所有可能的平均命令放置。我真的被困住了，因为我看起来对我来说似乎是正确的。另外，我对编程很新，所以我的代码可能不是非常pythonic。有人能指出出了什么问题吗？

import sys,string
import numpy as np
from math import *
import fileinput

infiles = ['stress1.txt']

oldlist = []
xlist = []
newlist = [0]

IN = fileinput.input(infiles)

for step in range(21): ## number of rows in stress1.txt
    line = IN.readline()
    [t,a] = string.split(line)
    time = float(t)
    acf = float(a)
    oldline = [time,acf]
    oldlist.append(oldline) ## nested list containing x and y values
for i in range(len(oldlist)):
    t11 = float(0.9*oldlist[i][0])
    t1 = float("{0:.4f}".format(t11))
    t22 = float(1.1*oldlist[i][0])
    t2 = float("{0:.4f}".format(t22))
    xlist.append(t1)
    xlist.append(t2)
xlist = [xlist[i:i+2] for i in range(0, len(xlist), 2)] ## nested list containing upper and lower bounds for each x. This list has the same size as 'oldlist'.
for i in range(len(oldlist)):
    for j in range(len(xlist)):
        if (xlist[i][0] <= oldlist[j][0] < xlist[i][1]):
            #print oldlist[j][0]
            newlist.append(oldlist[j][0])
    #print '\n'
    mean = sum(newlist)/float(len(newlist)) ## not giving the right average
    print mean

我已将我的问题编辑为包含stress1.txt：

0       63.97308696
0.005   62.68978803
0.01    58.95890345
0.015   53.11671683
0.02    45.64732412
0.025   37.10669444
0.03    28.05011931
0.035   18.98414178
0.04    10.34110231
0.045   2.470985737
0.05    -4.356736338
0.055   -9.947472597
0.06    -14.17532845
0.065   -16.97779073
0.07    -18.35134411
0.075   -18.34723586
0.08    -17.0675793
0.085   -14.66065262
0.09    -11.3157742
0.095   -7.257500157
0.1     -2.7383312

代码应该平均每个'块'，如下所示。初始块仅包含单个值，因此它本身就是平均值。后面的块有多个值，必须进行平均和输出。{抱歉使这个线程如此冗长}

Answer 1

如果我正确理解了你的目标，你需要在每次迭代开始时使用一个空的newlist []。如果你没有把它清空，那就充满了以前的街区＆＃39;值。

for i in range(len(oldlist)):

    #Make it empty
    newlist = []

    for j in range(len(xlist)):
        if (xlist[i][0] <= oldlist[j][0] and  oldlist[j][0] <= xlist[i][1]):
            newlist.append(oldlist[j][0])
    print(repr(newlist))
    mean = sum(newlist)/float(len(newlist))
    print(mean)

产生输出：

[0.0]
0.0
[0.005]
0.005
[0.01]
0.01
[0.015]
0.015
[0.02]
0.02
[0.025]
0.025
[0.03]
0.03
[0.035]
0.035
[0.04]
0.04
[0.045]
0.045
[0.045, 0.05, 0.055]
0.04999999999999999
[0.05, 0.055, 0.06]
0.055
[0.055, 0.06, 0.065]
0.06
[0.06, 0.065, 0.07]
0.065
[0.065, 0.07, 0.075]
0.07
[0.07, 0.075, 0.08]
0.07500000000000001
[0.075, 0.08, 0.085]
0.08
[0.08, 0.085, 0.09]
0.085
[0.085, 0.09, 0.095]
0.09000000000000001
[0.09, 0.095, 0.1]
0.09500000000000001
[0.09, 0.095, 0.1]
0.09500000000000001

在python

1 个答案: