Question

我有实体用户，示例计数为90355，我需要100个用户，并对此用户执行逻辑操作。接下来100使用，这是我有但当我发现所有我的服务器下拉列表如何解决这个问题？

public function find()
{
    $developers = $this->em->getRepository('ArtelProfileBundle:Users')->findBy(array(), array('id' => 'desc'));
    foreach ($developers as $developer) {
       $this->getApiFullContact($developer);
    }
    return true;
}

我觉得像这个函数但是setFirstResult和setMaxResults动态变量？

    public function getPaginationUser()
{
    $qb = $this->getEntityManager()->createQueryBuilder('d');
    $qb
        ->select('d')
        ->from('ArtelProfileBundle:Users', 'd')
        ->setFirstResult(0)
        ->setMaxResults(100)
        ->orderBy('d.id', 'DESC')
        ->getQuery()
        ->getResult()
    ;
    $query = $qb->getQuery();
    $results = $query->getResult();

    return $results;
}

这次迭代怎么办？

Answer 1

完全工作示例在这里 - ＆gt; Using limit and offset in doctrine query builder for manual pagination。我只是提供您需要先了解的代码。

这是它的工作方式，对我来说这是最好的做法！也许不适合所有人！

请求转到控制器
控制器呼叫服务
使用Trait
服务从存储库中提取数据
存储库将结果返回给服务
服务将结果传递给工厂
工厂创建结果模型
工厂将结果模型返回服务
服务将结果模型返回给控制器

<强> REPO

namespace Application\BackendBundle\Repository;

use Doctrine\ORM\EntityRepository;
use Doctrine\ORM\Query;

class StudentRepository extends EntityRepository
{
    /**
     * @param string|null $name
     * @param int         $limit
     * @param int         $offset
     *
     * @returns array
     */
    public function findPaginatedByName($name, $limit, $offset)
    {
        $qb = $this->createQueryBuilder('s');

        if ($name) {
            $qb->where('s.name = :name')->setParameter('name', $name);
        }

        $qb->setMaxResults($limit)->setFirstResult($offset);

        return $qb->getQuery()->getResult(Query::HYDRATE_SIMPLEOBJECT);
    }

    /**
     * @param string|null $name
     *
     * @return int
     */
    public function findPaginatedByNameCount($name)
    {
        $qb = $this->createQueryBuilder('s')->select('COUNT(s)');

        if ($name) {
            $qb->where('s.name = :name')->setParameter('name', $name);
        }

        return $qb->getQuery()->getResult(Query::HYDRATE_SINGLE_SCALAR);
    }
}

PAGER TRAIT

namespace Application\BackendBundle\Util;

trait PagerTrait
{
    public function getPage($page = 1)
    {
        if ($page < 1) {
            $page = 1;
        }

        return floor($page);
    }

    public function getLimit($limit = 20)
    {
        if ($limit < 1 || $limit > 20) {
            $limit = 20;
        }

        return floor($limit);
    }

    public function getOffset($page, $limit)
    {
        $offset = 0;
        if ($page != 0 && $page != 1) {
            $offset = ($page - 1) * $limit;
        }

        return $offset;
    }
}

<强>服务

namespace Application\BackendBundle\Service;

use Application\BackendBundle\Factory\StudentFactoryInterface;
use Application\BackendBundle\Model\Student\Result;
use Application\BackendBundle\Repository\StudentRepository;
use Application\BackendBundle\Util\PagerTrait;

class StudentService implements StudentServiceInterface
{
    use PagerTrait;

    private $studentRepository;
    private $studentFactory;

    public function __construct(
        StudentRepository $studentRepository,
        StudentFactoryInterface $studentFactory
    ) {
        $this->studentRepository = $studentRepository;
        $this->studentFactory = $studentFactory;
    }

    /**
     * @param string $name
     * @param int    $page
     * @param int    $limit
     *
     * @return Result
     */
    public function get($name, $page, $limit)
    {
        $page = $this->getPage($page);
        $limit = $this->getLimit($limit);
        $offset = $this->getOffset($page, $limit);
        $total = 0;

        $result = $this->studentRepository->findPaginatedByName($name, $limit, $offset);
        if ($result) {
            $total = $this->studentRepository->findPaginatedByNameCount($name);
        }

        return $this->studentFactory->createStudentResult($result, $name, $page, $limit, $total);
    }
}

Answer 2

我把这个例子从我发现的几件事中扔了出来，似乎有效。这是非常基本的，但这是一个开始。

回答：Doctrine2 Paginator getting total results

Symfony文档：Querying for Objects Using Doctrine's Query Builder

$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$username = $_POST['username'];

$flen = strlen($firstname);
$llen = strlen($lastname);
$c = $flen + $llen;

if ($flen>0) {
  $fname = "firstname = '$firstname'" ;
}

if ($c=2) {
  $com =  "," ;
}

if ($llen>0) {
  $lname = "lastname = '$lastname'" ;
}

$sql = "update employee set " . $fname . $com . $lname . "
where username = '$username' ";

    if ($conn->query($sql) === TRUE) {
        echo "Record updated successfully";
    }

    else{
    echo "error: $sql. " . mysqli_error($conn);
    }
mysqli_close($conn);
?>

Answer 3

这是未经测试的，但我认为这应该有效：

public function find($offset = 0)
{
    $developers = $this->em->getRepository('ArtelProfileBundle:Users')->findBy(array(), array('id' => 'desc'), 100, $offset);

    foreach ($developers as $developer) {
       $this->getApiFullContact($developer);
    }

    if (count($developers) < 100){
        $offset = $offset + 100;
        $this->find($offset)
    }      

    return new Response("finished!");  

}

Answer 4

我如何在 symfony 上进行分页

/**
 * @Route("", name="admin_number_pool", methods={"GET"})
 */
public function index(NumberPoolRepository $repo, NumberPoolCategoryRepository $categories, Request $request): Response
{
    $page = $request->query->get('page', 1);
    $limit = 10;
    $pagesCount = ceil(count($repo->findAll()) / $limit);
    $pages = range(1, $pagesCount);
    $pools = $repo->findBy([], [], $limit, ($limit * ($page - 1)));


    return $this->render('admin/number-pool/index.html.twig', [
        'numberPools' => $pools,
        'categories' => $categories->findAll(),
        'pages' => $pages,
        'page' => $page,
    ]);
}

Symfony Doctrine Pagination

4 个答案: