我有以下表结构。
TableA TableB TableC
- MID - PID - PID
- NAME - INIT_DATE - MID
这是我需要转换为Linq的SQL查询
SELECT TOP 10 TableA.NAME,
COUNT(TableB.INIT_DATE) AS [TOTALCOUNT]
FROM TableC
INNER JOIN TableA ON TableC.MID = TableA.MID
LEFT OUTER JOIN TableB ON TableC.PID = TableB.PID
GROUP BY TableA.NAME
ORDER BY [TOTALCOUNT] DESC
我尝试使用此Linq查询重现上述查询:
iqModel = (from tableC in DB.TableC
join tableA in DB.TableA on tableC.MID equals tableA.MID
select new { tableC, tableA } into TM
join tableB in DB.TableB on TM.tableC.PID equals J.PID into TJ
from D in TJ.DefaultIfEmpty()
select new { TM, D } into MD
group MD by MD.TM.tableA.NAME into results
let TOTALCOUNT = results.Select(item=>item.D.INIT_DATE).Count()
orderby TOTALCOUNT descending
select new SelectListItem
{
Text = results.Key.ToString(),
Value = TOTALCOUNT.ToString()
}).Take(10);
但我认为我做错了。
LINQ和SQL的输出不一样。我认为JOIN或GROUPBY是正确的。
编辑: -
我也尝试了以下Linq查询,但仍然无法正常工作。
var iqModel = (from c in DB.TableC
join a in DB.TableA on c.MID equals a.MID
join b in DB.b on c.PID equals b.PID into b_join
from b in b_join.DefaultIfEmpty()
select new SelectListItem { Text = a.NAME, Value = b.INIT_DATE != null ? b.INIT_DATE.ToString() : string.Empty });
var igModel = iqModel.GroupBy(item => item.Text);
var result = igModel.OrderByDescending(item => item.Select(r => r.Value).Count());
我想了解我做错了什么以及如何解决。
我是LINQ to SQL的新手我认为在上面的LINQ中我真的通过添加更多选择使它变得复杂。
答案 0 :(得分:1)
我认为差异是因为SQL COUNT(field)
函数不包含NULL
值。在LINQ中没有直接的等效构造,但它可以用Count(e => e.Field != null)
或类似的模拟(这似乎产生更好的SQL):
var query =
(from a in db.TableA
join c in db.TableC on a.MID equals c.MID
join b in db.TableB on c.PID equals b.PID into joinB
from b in joinB.DefaultIfEmpty()
group b by a.Name into g
let TOTALCOUNT = g.Sum(e => e.INIT_DATE != null ? 1 : 0)
orderby TOTALCOUNT descending
select new SelectListItem { Text = g.Key, Value = TOTALCOUNT }
).Take(10);
生成以下SQL
SELECT TOP (10)
[Project1].[C2] AS [C1],
[Project1].[Name] AS [Name],
[Project1].[C1] AS [C2]
FROM ( SELECT
[GroupBy1].[A1] AS [C1],
[GroupBy1].[K1] AS [Name],
1 AS [C2]
FROM ( SELECT
[Join2].[K1] AS [K1],
SUM([Join2].[A1]) AS [A1]
FROM ( SELECT
[Extent1].[Name] AS [K1],
CASE WHEN ([Extent3].[INIT_DATE] IS NOT NULL) THEN 1 ELSE 0 END AS [A1]
FROM [dbo].[TableAs] AS [Extent1]
INNER JOIN [dbo].[TableCs] AS [Extent2] ON [Extent1].[MID] = [Extent2].[MID]
LEFT OUTER JOIN [dbo].[TableBs] AS [Extent3] ON [Extent2].[PID] = [Extent3].[PID]
) AS [Join2]
GROUP BY [K1]
) AS [GroupBy1]
) AS [Project1]
ORDER BY [Project1].[C1] DESC
答案 1 :(得分:0)
我假设您在结果查询中未看到“ group by ”命令,而不是使用“ distinct ”命令。我是对的吗?
第一个查询使用TableA.NAME进行区分,然后在子查询的帮助下计算COUNT(TableB.INIT_DATE),如下所示:
select distinct1.Name, (select count() from *join query* where Name = distinct1.Name)
from (select distinct Name from *join query*) as distinct1
如果是这样,不用担心。因为从linq到真正的t-sql脚本的转换有时非常不可预测(你不能强迫它们相等,只有当查询非常简单时),但是两个查询彼此相同并返回相同的结果(比较它们以确保)