Question

我对PHP CURL很新，并试图调用API来进行图像上传（一次多个文件）。 API文档在CURL中给出了以下示例。我已经过测试，它正在运行。

Person p = person.get(1);
String city = p.getAddress().getCity();
String email = p.getContact().getEmail();

现在我需要将其转换为PHP Curl。出于某种原因，我总是得到错误“imageData”param无效。有人可以帮忙吗

curl -H "Authorization: Bearer 123456789" -i -X POST -F "whitespace=1" \
 -F "imageData[]=@/path/to/images/milk.jpg" \
 -F "imageData[]=@/path/to/images/peas.jpg" \
 https://mytestapi.com/1.0/uploadimages

Answer 1

尝试提供完整的图片路径，而不是'@/path/to/images/milk.jpg';

这是更新的代码：

$token = '123456789';
$imgUrl = 'https://mytestapi.com/1.0/uploadimages';


$data_to_post = array();
$data_to_post['whitespace'] = '1';
$data_to_post['imageData'][] = "@".$imgUrl.'/path/to/images/milk.jpg';
$data_to_post['imageData'][] = "@".$imgUrl.'/path/to/images/peas.jpg';


$curl = curl_init($imgUrl);
curl_setopt($curl, CURLOPT_HTTPHEADER, ['Authorization: Bearer '.$token]);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl,CURLOPT_POST, 1);
curl_setopt($curl,CURLOPT_POSTFIELDS, $data_to_post);
$data = json_decode(curl_exec($curl));
$responseCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);
curl_close($curl);

var_dump($data);

如果这不起作用，请告诉我。

Answer 2

我自己解决了这个问题。不得不使用php curl文件创建使其工作而不是附加'@'

http://www.php.net/manual/es/function.curl-file-create.php

Answer 3

如何使用PHP cURL上传文件

<?php 

// Helper function courtesy of https://github.com/guzzle/guzzle/blob/3a0787217e6c0246b457e637ddd33332efea1d2a/src/Guzzle/Http/Message/PostFile.php#L90
function getCurlValue($filename, $contentType, $postname)
{
    // PHP 5.5 introduced a CurlFile object that deprecates the old @filename syntax
    // See: https://wiki.php.net/rfc/curl-file-upload
    if (function_exists('curl_file_create')) {
        return curl_file_create($filename, $contentType, $postname);
    }

    // Use the old style if using an older version of PHP
    $value = "@{$this->filename};filename=" . $postname;
    if ($contentType) {
        $value .= ';type=' . $contentType;
    }

    return $value;
}

$filename = '/path/to/file.jpg';
$cfile = getCurlValue($filename,'image/jpeg','cattle-01.jpg');

//NOTE: The top level key in the array is important, as some apis will insist that it is 'file'.
$data = array('file' => $cfile);

$ch = curl_init();
$options = array(CURLOPT_URL => 'http://your/server/api/upload',
             CURLOPT_RETURNTRANSFER => true,
             CURLINFO_HEADER_OUT => true, //Request header
             CURLOPT_HEADER => true, //Return header
             CURLOPT_SSL_VERIFYPEER => false, //Don't veryify server certificate
             CURLOPT_POST => true,
             CURLOPT_POSTFIELDS => $data
            );

curl_setopt_array($ch, $options);
$result = curl_exec($ch);
$header_info = curl_getinfo($ch,CURLINFO_HEADER_OUT);
$header_size = curl_getinfo($ch, CURLINFO_HEADER_SIZE);
$header = substr($result, 0, $header_size);
$body = substr($result, $header_size);
curl_close($ch);

?>

<!doctype html>
<html>
<head>
    <meta charset="utf-8">
    <title>File Upload results</title>
</head>
<body>
    <p>Raw Result: <?=$result?>
    <p>Header Sent: <?=$header_info?></p>
    <p>Header Received: <?=$header?></p>
    <p>Body: <?=$body?></p>
</body>
</html>

图像上传CURL命令到PHP Curl

3 个答案: