Question

我如何更改网址中的参数
例如https://example.com/r.php?12345到https://example.com/12345？

nginx conf文件：

server {
    listen       80;
    server_name  example.com;
    rewrite_log on;
    # note that these lines are originally from the "location /" block
    root   /usr/share/nginx/example.com;
    index index.php index.html index.htm;
    location / {
        try_files $uri $uri/ =404;
    }
    error_page 404 /404.html;
    error_page 500 502 503 504 /50x.html;
    location = /50x.html {
        root /usr/share/nginx/html;
    }
    location ~ \.php$ {
        try_files $uri =404;
        fastcgi_pass 127.0.0.1:9000;
        fastcgi_index index.php;
        fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
        include fastcgi_params;
    } 
}

以及添加块的位置在conf文件里面？

Answer 1

如果URI未映射到本地文件，则try_files的最后一个元素是默认操作。所以用所需的重写替换你的404错误。尝试：

location / {
    try_files $uri $uri/ /r.php?$uri;
}

有关详细信息，请参阅this document。

在url中创建nginx更改参数

1 个答案: