我是Python的新手。 我的一个线程回调代码在我的raspi上工作正常。
import RPi.GPIO as GPIO
GPIO.setmode(GPIO.BCM)
import time
from daemon import runner
GPIO.setup(23, GPIO.IN, pull_up_down=GPIO.PUD_DOWN) # float switch goes down (closed to open) => low water level
GPIO.setup(24, GPIO.IN, pull_up_down=GPIO.PUD_UP) # float switch goes up (opened to close) => high water level
def callback_lowlevel(channel):
if GPIO.input(channel):
print "Low water level in the sump detected"
else:
print "Water level in the sump returned to normal"
def callback_highlevel(channel):
if GPIO.input(channel):
print "High water level in the sump detected"
else:
print "Water level in the sump returned to normal"
GPIO.add_event_detect(23, GPIO.BOTH, callback=callback_lowlevel, bouncetime=1000)
GPIO.add_event_detect(24, GPIO.BOTH, callback=callback_highlevel, bouncetime=1000)
如果我开始这样的无限循环:
try:
print "Waiting for events"
while True:
time.sleep(1)
except KeyboardInterrupt:
GPIO.cleanup() # clean up GPIO on CTRL+C exit
GPIO.cleanup() # clean up GPIO on normal exit
有效。
但如果我" daemonize"它与守护进程库,我的线程回调不再工作。
class App(): # Daemon content, not doing much, sleeping mostly, to lower CPU footprint
def __init__(self):
self.stdin_path = '/dev/null'
self.stdout_path = '/dev/stdout'
self.stderr_path = '/dev/stdout'
self.pidfile_path = '/var/run/aquamonitor.pid'
self.pidfile_timeout = 5
def run(self):
Logger("Starting monitoring")
while True:
time.sleep(1) # Sleep most of time to be not too CPU intensive
app = App() # Init the App
daemon_runner = runner.DaemonRunner(app) # Run as a daemon
daemon_runner.do_action() # Just do it
我做错了什么?它作为守护进程的事实是否会改变我应该编写线程回调的方式?
答案 0 :(得分:1)
我有同样的问题,我想我正在将回调注册到错误的线程。所以,简而言之,请确保在App类的run方法中调用GPIO.add_event_detect,就在循环之前。