is_dir在Windows平台上没有使用codeginiter

Question

我在CI控制器中有一个数组，如下所示

Array
        (
            [user_id] => 109676506743696803215
            [sub_dirs] => Array
                (
                    [0] => Array
                        (
                            [legacyListID] => 00984bc3-aaa3-4519-be03-09a73623f2b1
                            [slug] => st-peters-model-school
                        )

                    [1] => Array
                        (
                            [legacyListID] => 092452b5-3bc1-4f8e-96d4-dfb96e3af9fc
                            [slug] => sri-aurobindo-international-school
                        )

                    [2] => Array
                        (
                            [legacyListID] => 0d65157d-9bf6-44e9-9b72-ab9e37faa130
                            [slug] => suprabhat-model-high-school
                        )

                    [3] => Array
                        (
                            [legacyListID] => 20358e6f-7b15-4efb-b259-e4a34fea37ad
                            [slug] => rushi-high-school
                        )

                    [4] => Array
                        (
                            [legacyListID] => 262c1151-d39c-4ae4-b9c9-f68fa606fda3
                            [slug] => vignan-high-school
                        )

                    [5] => Array
                        (
                            [legacyListID] => 5d064b73-97f0-43b6-8aa6-da98cbca646e
                            [slug] => smart-kidz-play-school
                        )

                    [6] => Array
                        (
                            [legacyListID] => 68015e74-bba8-460a-93f7-282c3bf7ddb8
                            [slug] => gurukila-vidyapeeth-high-school
                        )

                    [7] => Array
                        (
                            [legacyListID] => 76ff39b9-e9a4-4b2b-bc8b-36e11089e3e7
                            [slug] => the-mothers-integral-school
                        )

                    [8] => Array
                        (
                            [legacyListID] => a31c7919-2007-4f83-8674-57010c43520f
                            [slug] => sr-digi-school
                        )

                    [9] => Array
                        (
                            [legacyListID] => cf078592-d7ce-46f6-b18c-8c6ead70f1d8
                            [slug] => gautami-talent-school
                        )

                    [10] => Array
                        (
                            [legacyListID] => eccebdea-8db9-4f45-8016-235a6a03ff6f
                            [slug] => anglist-high-school
                        )

                    [11] => Array
                        (
                            [legacyListID] => fdc44658-bed0-458e-85b0-6897d1175a93
                            [slug] => pratibha-high-school
                        )

                )

这里user_id是文件夹名称，我在文件夹中有sub_dirs。 sub_dirs变量包含在user_id文件夹中具有实际子目录名称的数据数组，以及用于重命名它的重命名参数（slug）。

我在做如下

foreach ($dirs as $dir) {

    $dirPath='images/profile/'.$dir['user_id'];

    if(is_dir($dirPath)){

        foreach ($dir['sub_dirs'] as $sub) {

            $subDir=$dirPath."/".$sub['legacyListID'];

            if(is_dir($subDir)){
                rename($subDir,$sub['slug']);
            }
        }

    }
}

我的操作系统是Windows。如果我错过了许可问题或者在codeigniter中这样做的帮助，你能帮助我吗？

仅供参考： images / profiles /（dir）/（subDir）位于根文件夹中

Answer 1

假设您的images文件夹位于应用程序路径中，您应该使用APPPATH CI变量：

FCPATH   -> '/'
BASEPATH -> '/system/'
APPPATH  -> '/application/'

Answer 2

将FCPATH用于目录位置

foreach ($dirs as $dir) {

    $dirPath = FCPATH . 'images/profile/'. $dir['user_id'];

    if(is_dir($dirPath)){

        foreach ($dir['sub_dirs'] as $sub) {

            $subDir = $dirPath ."/". $sub['legacyListID'];

            if(is_dir($subDir)){
                rename($subDir, $sub['slug']);
            }
        }

    }
}

确保您的images文件夹位于主目录

中

application

images >

images > profile

您也可以使用dirname(FCPATH) . '/images/profile/'. $dir['user_id'];

Answer 3

使用PHP中的scandir函数解决它，如下所示

foreach ($dirs as $dir) {
       $path="images/profiles";

       $curDir=$path."/".$dir['user_id'];

           if(is_dir($curDir)){

            foreach ($dir['sub_dirs'] as $i => $sub) {

                foreach (scandir($curDir) as $subDir) {

                    if($subDir == $sub['legacyListID']){

                        $old=$curDir."/".$sub['legacyListID'];
                        $rename=$curDir."/".$sub['slug'];

                        rename($old, $rename);
                    }

                }
            }

           }
        }

基本上dirs是实际的数组，它包含所有目录和子目录，并在其中重命名数组。

所以我扫描了每个目录并获得了所有子目录，因此每当有匹配时我都会更名。

理解重命名不会与for循环一起工作。我们首先在目录中获取所有子目录并与您自己的数组匹配，然后重命名它。

ALL GOOD：）