Question

我在php中有这个数组，我想选择那些有dob的所有casenumber，然后选择那些没有任何dob的所有链接。我怎么能在PHP中做到这一点

Array
(
    [links] => Array
        (
            [0] => inquiryDetail.jis?caseId=0101SP085622015&loc=3&detailLoc=DV
            [1] => inquiryDetail.jis?caseId=0101SP096462015&loc=3&detailLoc=DV
            [2] => inquiryDetail.jis?caseId=050200173642014&loc=20&detailLoc=DSCIVIL
            [3] => inquiryDetail.jis?caseId=CAL1432003&loc=65&detailLoc=PGV
        )
    [case_number] => Array
        (
            [0] => 0101SP085622015
            [1] => 0101SP096462015
            [2] => 050200173642014
            [3] => CAL1432003
        )
    [persons] => Array
        (
            [0] => Walker, Rosemary
            [1] => Walker, Rosemary
            [2] => Walker, Rosemary
            [3] => Walker, Rosemary
        )
    [dob] => Array
        (
            [0] => 11/1961
            [1] => 11/1961
        )
    [Party_Type] => Array
        (
            [0] => Defendant
            [1] => Defendant
            [2] => Defendant
            [3] => Defendant
        )

    [Court] => Array
        (
            [0] => Baltimore City District Court 1400 North Ave.
            [1] => Baltimore City District Court 1400 North Ave.
            [2] => Upper Marlboro District Court
            [3] => Prince George\'s County Circuit Court
        )
    [Case_Type] => Array
        (
            [0] => Domestic Violence
            [1] => Domestic Violence
            [2] => CONT
            [3] => CIVIL
        )

    [Case_Status] => Array
        (
            [0] => CLOSE
            [1] => CLOSE
            [2] => ACTIVE
            [3] => ACTIVE
        )
    [Filing_Date] => Array
        (
            [0] => 09/04/2015
            [1] => 11/25/2015
            [2] => 07/24/2014
            [3] => 11/18/2014
        )

)

这里所有都是互相关联的键。请帮忙

Answer 1

如果每个子阵列的索引匹配，则此解决方案有效。如果没有，你应该用子阵列之间的关联来澄清你的问题。

$ array - 您的输入数据。

您将获得包含搜索值的$ result数组。

$result = array(
   'links_without_dob' => array(),
   'case_number_with_dob' => array() 
);
foreach($array['dob'] as $k => $v) {
  $result['case_number_with_dob'][] = $array['case_number'][$k];
}
foreach($array['links'] as $k => $v) {
  if (array_key_exists($k, $array['dob'])) continue;
  $result['links_without_dob'][] = $v;
}

我很高兴看到任何有关改进此解决方案的建议。

需要有关PHP数组过滤的帮助

1 个答案: