我有一个页面index.php,我添加了一个与数据库连接的搜索表单。这样,当用户搜索任何单词时,结果将显示在数据库中。在页面上生成结果后,我希望用户将结果导出到.doc文件中。
我只想将查询结果放入.doc文件中,但出于某些原因我得到一个空白的.doc文件。
以下是我的代码:
搜索表单:
<form id="searchform" method="post">
<input type="text" name="searchit" id="searchit" class="txt" />
<input type="submit" value="Search" id="button" class="button" />
</form>
查询:
<?php
include("database.php");
$term = strip_tags(substr($_POST['searchit'],0, 100));
$term = $mysqli->real_escape_string($term);
if($term=="") {
echo "<div class='error'>Enter Something to search</div>";
exit();
}
termcheck($term, $mysqli);
function termcheck($term, $mysqli){
$qry="Select * from pogel where title = '$term'";
if($result = $mysqli->query($qry)){
$num_rows = $result->num_rows;
if($num_rows > 0) {
while($row = $result->fetch_assoc())
{
echo "Stem : ".$row['title']."<br>";
}
}
}
}
?>
答案 0 :(得分:1)
好像你在POST中没有这把钥匙。
如果剧本没有这样的元素,你可以试试这个:
$searchit = filter_input(INPUT_POST, 'searchit');
if(!$searchit) {
echo "<div class='error'>Enter Something to search</div>";
exit();
}
$term = strip_tags(substr($searchit,0, 100));
$term = $mysqli->real_escape_string($term);
尝试生成doc文件:
<?php
include("database.php");
$term = strip_tags(substr($_POST['searchit'],0, 100));
$term = $mysqli->real_escape_string($term);
if($term=="") {
echo "<div class='error'>Enter Something to search</div>";
exit();
}
$output = termcheck($term, $mysqli);
function termcheck($term, $mysqli){
$qry = "Select * from pogel where title = '$term'";
$result = '';
if($result = $mysqli->query($qry)){
$num_rows = $result->num_rows;
if($num_rows > 0) {
while($row = $result->fetch_assoc()) {
$result .= "Stem : ".$row['title']."<br>";
}
}
}
return $result;
}
ob_flush();
header("Content-type: application/vnd.ms-word");
header("Content-Disposition: attachment;Filename=document_name.doc");
echo $output;
//ob_flush_clean() might be useful here, but not sure
?>