Question

我正在尝试使用包装元素来解组XML。

XML看起来：

<?xml version="1.0" encding="utf-8"?>
<Output xmlns="_xxx_" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
   <Companies>
      <Company>
         ...
      </Company>
      <Company>
         ...
      </Company>
      ...
   </Companies>
   <People>
      <Person>
         ...
      </Person>
      <Person>
         ...
      </Person>
      ...
   </People>
   <Relations>
      <Relation>
         ...
      </Relation>
      <Relation>
         ...
      </Relation>
      ...
   </Relations>
   <Info ... />
</Output>

我想在列表中包含补充，人员和关系。我尝试使用此代码，但它不起作用：

Java代码

输出继电器

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "Output", namespace = "_xxx_")
@XmlType(propOrder={"companies", "people", "relations", "info"})
public class Output {

   @XmlElementWrapper(name = "Companies")
   @XmlElement(name = "Company" type = Company.class)
   private List<Company> companies;

   @XmlElementWrapper(name = "People")
   @XmlElement(name = "Person", type = Person.class)
   private List<Person> people;

   @XmlElementWrapper(name = "Relations")
   @XmlElement(name = "Relation", type = Relation.class)
   private List<Relation> relations;

   @XmlElement(name = "Info")
   private Info info;

   public Output() {
      this.companies = new ArrayList<>();
      this.people = new ArrayList<>();
      this.relations = new ArrayList<>();
   }

   public List<Company> getCompanies() {
       return companies;
   }

   public void setCompanies(List<Company> companies) {
       this.companies = companies;
   }

   public List<Person> getPeople() {
       return people;
   }

   public void setPeople(List<Person> people) {
       this.people = people;
   }

   public List<Relation> getRelations() {
       return relations;
   }

   public void setRelations(List<Relation> relations) {
       this.relations = relations;
   }

   public Info getInfo() {
       return info;
   }

   public void setInfo(Info info) {
       this.info = info;
   } 
}

例如 Company 看起来（其他类相似）

@XmlRootElement(name = "Company")
public class Company {
   ...
}

如果我使用它，它会创建空列表，但是，如果我将代码更改为：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "Output", namespace = "_xxx_")
@XmlType(propOrder={"companies", "people", "relations", "info"})
public class Output {
   @XmlElement(name = "Companies")
   private Companies companies;

   @XmlElement(name = "People")
   private People people;
   ....

   public Companies getCompanies() {
       return companies;
   }

   public void setCompanies(Companies companies) {
       this.companies = companies;
   }

   ...
}

其中公司类看起来：

@XmlRootElement(name = "Companies")
@XmlAccessorType (XmlAccessType.FIELD)
public class Companies {

   @XmlElement(name = "Company")
   private List<Company> companies;

   public List<Company> getCompanies() {
       return companies;
   }

   public void setCompanies(List<Company> companies) {
       this.companies = companies;
   }
}

它工作正常，但它不是一个很好的解决方案。

有谁能告诉我这里有什么问题？谢谢:)）

Answer 1

我使用link上的说明解决了我的问题。我使用映射到java.util.Map。

JAXB将XML元素解组为对象包装器

1 个答案: