我尝试查询以查找“Lutin”提供的“Enfants”。我得到了Lutin,我在“Enfant”上创建了一个查询
public class SeeEnfantForLutinActivity extends AppCompatActivity {
Lutin lutin;
String lutin_ID;
List<Enfant> list_enfants = new ArrayList<>();
ListView list;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_see_enfant_for_lutin);
TextView label = (TextView) findViewById(R.id.label_enfant_lutin);
Bundle bundle = getIntent().getExtras();
lutin = bundle.getParcelable("LUTIN");
lutin_ID = bundle.getString("LUTIN_ID");
label.setText(getString(R.string.label_enfant_for_lutin, lutin.getName()));
list = (ListView) findViewById(R.id.list_enfant_lutin);
ParseQuery<Enfant> query = ParseQuery.getQuery("Enfant");
query.whereEqualTo("Lutin",lutin);
query.findInBackground(new FindCallback<Enfant>() {
@Override
public void done(List<Enfant> objects, ParseException e) {
if (e == null) {
for (Enfant en : objects) {
list_enfants.add(en);
}
ArrayAdapter<Enfant> enfantArrayAdapter =
new ArrayAdapter<Enfant>(SeeEnfantForLutinActivity.this, android.R.layout.simple_list_item_1, list_enfants);
list.setAdapter(enfantArrayAdapter);
} else {
e.printStackTrace();
}
}
});
}
}
但是在线: query.findInBackground(new FindCallback(){
抛出异常:
com.parse.ParseException:java.lang.IllegalStateException:无法编码与未保存的ParseObject的关联
哪里有错误?我用原始对象(String,int,...)
成功完成了同样的事情答案 0 :(得分:0)
试试这个
ParseQuery<ParseObject> query = ParseQuery.getQuery("yourTable");
query.whereEqualTo("Lutin",lutin);
query.findInBackground(new FindCallback<ParseObject>() {
@Override
public void done(List<ParseObject> parseObjects, ParseException e) {
if (e == null) {
//do your work
}else{
}
}
});