我有一些文字字段。我想在所有文本字段中输入值后启用提交按钮。我试过了。任何人都可以建议做什么! 这是我将其写入onCreate方法的代码。
confrimPasswordButton.setEnabled(false);
passCheck = confirmPasswordText.getText().toString();
passwordNew = newPasswordText.getText().toString();
passwordExist = exstingPasswordText.getText().toString();
答案 0 :(得分:2)
您应该实施TextWatcher。选择最适合您的三种界面方法之一,并将您的实施方式传递给EditText
到addTextChangedListener()。如果您坚持实施 - 互联网上有很多关于如何实施TextWatcher
的资源。
答案 1 :(得分:0)
将TextWatcher
添加到您的EditText
passwordEditText.addTextChangedListener(passwordWatcher);
以下是passwordWatcher
private TextWatcher passwordWatcher = new TextWatcher() {
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(//password matches with value of edittext){
button.setVisibility(View.VISIBLE); // Make your button visible
}
}
public void afterTextChanged(Editable s) {
if (s.length() == 0) {
button.setVisibility(View.GONE);
} else{
//code to show some some error
}
}
};
}
注意:按照模式,复制和粘贴可能会导致一些错误,因为我没有检查代码。
答案 2 :(得分:0)
检查以下解决方案
passwordExist.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence arg0, int arg1, int arg2, int arg3) {
}
@Override
public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
int arg3) {
}
@Override
public void afterTextChanged(Editable et) {
if((passwordExist.getText().length()>0)
{
button.setVisibility(View.GONE); ///PERFROM ACTION WHAT EVER YOU WANT TO DO WHEN EDIT TEXT LENGTH GREATER THAN 0
}
else{
button.setVisibility(View.VISIBLE);///PERFROM ACTION WHAT EVER YOU WANT TO DO WHEN EDIT TEXT LENGTH EQUAL TO 0
}
}
});