我正在尝试将数据发送到WampServer。我正在使用HttpUrlConnection,我不知道如何发送数据 - 可能是JSON格式或XML。我已经使用内容值来保存我想要发送的变量的值,但我不知道如何在PHP脚本中将它们发送到POST方法。
这是PHP代码:
<?php
if(isset($_POST['txtname'])&&isset($_POST['txtemail']))
{
require ('config.php');
$con=mysqli_connect($servername,$username,$password,$db);
$txtname=$_POST['txtname'];
$txtemail=$_POST['txtemail'];
mysqli_query($con,"insert into users (name,email) values('$txtname','$txtemail') ");
echo "Inserted";
}
?>
这是Java代码:
package com.subhi.addtoserver;
import android.app.ProgressDialog;
import android.content.ContentValues;
import android.os.AsyncTask;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import java.io.IOException;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;
public class MainActivity extends AppCompatActivity {
public EditText name,email;
Button add;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
name=(EditText)findViewById(R.id.name);
email=(EditText)findViewById(R.id.email);
add=(Button)findViewById(R.id.add);
add.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
InsertData task1 = new InsertData();
String name1, email1;
name1 = name.getText().toString();
email1 = email.getText().toString();
task1.execute("http://192.168.1.100/add/index.php", name1, email1);
}
});
}
private class InsertData extends AsyncTask<String,Void,Boolean>
{
ProgressDialog dialog=new ProgressDialog(MainActivity.this);
@Override
protected Boolean doInBackground(String... urls) {
for (String url: urls)
{
try {
ContentValues contentValues=new ContentValues();
contentValues.put("txtname",urls[1]);
contentValues.put("txtemail",urls[2]);
URL url1 =new URL(urls[0]);
HttpURLConnection urlConnection=(HttpURLConnection)url1.openConnection();
urlConnection.connect();
} catch (MalformedURLException e) {
Toast.makeText(getApplicationContext(),e.toString(),Toast.LENGTH_LONG).show();;
e.printStackTrace();
return false;
} catch (IOException e) {
Toast.makeText(getApplicationContext(),e.toString(),Toast.LENGTH_LONG).show();;
e.printStackTrace();
return false;
}
}
return true;
}
@Override
protected void onPreExecute() {
dialog.setMessage("Sending Data....");
dialog.show();
}
@Override
protected void onPostExecute(Boolean result) {
if(result==true)
{
Toast.makeText(getApplicationContext(),"Insert Success",Toast.LENGTH_LONG).show();;
}
else {
Toast.makeText(getApplicationContext(),"Insert Fail",Toast.LENGTH_LONG).show();;
}
dialog.dismiss();
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
答案 0 :(得分:0)
这是你应该发送的方式。
echo json_encode(array("txtname"=>$txtname, "txtemail"=>'$txtemail'));
客户端在android中。 我希望你知道,如何从json获取值。
答案 1 :(得分:-1)
这个youtube URL用于将数据android传递给带有SQL服务器的PHP。 网址:https://www.youtube.com/watch?v=D86beKXvjd0
试试这个