Question

尝试在django中获得manytomany关系，但我收到以下错误 -

尝试在序列化程序GenreSerializer上获取字段name的值时，
获得AttributeError。序列化程序字段可能名称不正确，并且与Movie实例上的任何属性或键都不匹配。原始异常文本是：'Movie'对象没有属性'name'。

这里有一个类似的答案，建议设置many=True，但它不起作用 - Attribute error when attempting to get a value for field

models.py

class Genre(models.Model):
  name = models.CharField(max_length=255,unique=True)

  def __unicode__(self):
    return self.name

class Movie(models.Model):
  mname = models.CharField(max_length=255)
  genres = models.ManyToManyField(Genre,related_name='movies')

  def __unicode__(self):
    return self.mname

serializers.py

class GenreSerializer(serializers.ModelSerializer):
  class Meta:
    model = Genre
    fields = ('name','id')

class MovieSerializer(serializers.ModelSerializer):
  genres = GenreSerializer(many=True, read_only=True)    

  class Meta:
    model = Movie
    fields = ('id','genres','mname')

urls.py

urlpatterns = [
url(r'^genres/$', views.GenreList.as_view()),
url(r'^genres/(?P<pk>[0-9]+)$', views.GenreDetail.as_view()),
]

urlpatterns = format_suffix_patterns(urlpatterns)

views.py

class GenreList(generics.ListCreateAPIView):
  queryset = Genre.objects.all()
  serializer_class = GenreSerializer


class GenreDetail(generics.RetrieveUpdateDestroyAPIView):
  serializer_class = GenreSerializer

  def get_queryset(self):
    genres = Genre.objects.get(pk=self.kwargs.get('pk', None))
    movies = Movie.objects.filter(genres=genres)
    return movies

Answer 1

与您的其他问题类似，您在GenreDetail视图中使用了错误的序列化程序。您需要为从get_queryset返回的模型类型添加序列化程序：

class GenreDetail(generics.RetrieveUpdateDestroyAPIView):
    serializer_class = MovieSerializer

    def get_queryset(self):
        genres = Genre.objects.get(pk=self.kwargs.get('pk', None))
        movies = Movie.objects.filter(genres=genres)
        return movies

尝试在序列化程序上获取字段值时的AttributeError

1 个答案: