我很难理解我做错了什么。基本上我只是想在我点击div时显示一个模态。但是,除了这个警告之外什么也没发生:
警告:React.createElement:type不应为null,未定义, 布尔值或数字。它应该是一个字符串(对于DOM元素)或a ReactClass(用于复合组件)。
以下是模态出现的组件:
import React from 'react';
import {ModalTrigger} from 'react-bootstrap';
import MyModal from './MyModal';
var PostTitle = React.createClass({
openPost : function() {
var postData = this.props.postData;
console.log("clicked - openPost");
return (
<ModalTrigger modal={<MyModal/>}>
</ModalTrigger>
)
},
render : function() {
var postData = this.props.postData;
return(
<div className="item" onClick={this.openPost}>
<div className="well">
<img src={postData.image}/>
<p>{postData.title}</p>
</div>
</div>
)
}
});
export default PostTitle;
这是MyModal组件:
import React from 'react';
import {Modal} from 'react-bootstrap';
var MyModal = React.createClass({
render : function() {
return (
<Modal {...this.props}>
<ul className="list-group">
<li className="list-group-item">Cras justo odio</li>
<li className="list-group-item">Dapibus ac facilisis in</li>
<li className="list-group-item">Morbi leo risus</li>
<li className="list-group-item">Porta ac consectetur ac</li>
<li className="list-group-item">Vestibulum at eros</li>
</ul>
</Modal>
)
}
});
export default MyModal;
答案 0 :(得分:2)
ModalTrigger
是deprecated on July 2015。
您可以在组件状态中存储是否必须显示模态。单击元素后,您将this.state.show
设置为true
。这将显示模态。关闭/隐藏模态后,将this.state.show
设置为false,不会显示模态。
var PostTitle = React.createClass({
getInitialState() {
return {show: false};
},
openPost : function() {
var postData = this.props.postData;
console.log("clicked - openPost");
this.setState({show: true});
},
closePost: function () {
this.setState({show: false});
},
render : function() {
var postData = this.props.postData;
return(
<div className="item" onClick={this.openPost}>
<MyModal show={this.state.show} onHide={this.closePost} />
<div className="well">
<img src={postData.image}/>
<p>{postData.title}</p>
</div>
</div>
)
}
});