Question

我在bash中有一个变量，比如说，

val="cmd arg1 arg2"

我想分成两部分，一部分是命令，另一部分是所有参数（即$0＆amp; $*）。我怎么能这样做？

它应该适用的示例案例：

val =“/ c / Program \ Files / Oracle / VirtualBox / vBoxManage.exe --help -ds”

val =“'/ c / Program Files / Oracle / VirtualBox / vBoxManage.exe' - help -ds”

val ='“/ c / Program Files / Oracle / VirtualBox / vBoxManage.exe” - help -ds'

val =“../ run dsa”

val =“/ fdfds / fds fds”

Answer 1

您可以尝试以下内容：

while read -r val
do
    echo "The input val is:==$val=="
    declare -a 'arr=('"$val"')'
    cmd=${arr[0]}
    echo "Command is: ==$cmd=="
    unset arr[0]
    for arg in "${arr[@]}"
    do
        echo "  argument is: ==$arg=="
    done
    echo
done <<EOF
cmd arg1 arg2
cmd "arg1 1" "arg2 2"
"../so me/cmd md" arg1 arg2
"../so me/cmd md" arg1 "arg2 2"
EOF

打印

The input val is:==cmd arg1 arg2==
Command is: ==cmd==
    argument is: ==arg1==
    argument is: ==arg2==

The input val is:==cmd "arg1 1" "arg2 2"==
Command is: ==cmd==
    argument is: ==arg1 1==
    argument is: ==arg2 2==

The input val is:=="../so me/cmd md" arg1 arg2==
Command is: ==../so me/cmd md==
    argument is: ==arg1==
    argument is: ==arg2==

The input val is:=="../so me/cmd md" arg1 "arg2 2"==
Command is: ==../so me/cmd md==
    argument is: ==arg1==
    argument is: ==arg2 2==

e.g。

val='"/c/Program Files/Oracle/VirtualBox/vBoxManage.exe" --help'
declare -a 'arr=('"$val"')'
cmd=${arr[0]}
unset arr[0]
args="${arr[@]}"
echo "cmd:==$cmd==  args:==$args=="

打印

cmd:==/c/Program Files/Oracle/VirtualBox/vBoxManage.exe==  args:==--help==

Bash将字符串拆分为位置参数

1 个答案: