我有一个jpql查询在select子句
中实例化一个java对象public List<ChampEtatOT> getEtatOT(Date dateDebut, Date dateFin) {
Query query = em.createQuery("SELECT NEW ChampEtatOT( ot.numero, uo.denominationFr, ot.etat, ot.dateDebutReelle , ot.dateFinReelle, :dateParam1, :dateParam2, :dateParam3) FROM ordre ot JOIN ot.unite uo")
.setParameter("dateParam1", dateDebut, TemporalType.DATE)
.setParameter("dateParam2", dateFin, TemporalType.DATE)
.setParameter("dateParam3", new Date("2015-01-01"), TemporalType.DATE);
return query.getResultList();
}
我放了3个参数,所以我可以在构造函数中传递它 我收到此错误
Caused by: Exception [EclipseLink-6137] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.QueryExceptionException Description: An Exception was thrown while executing a ReportQuery with a constructor expression: java.lang.NoSuchMethodException: dz.elit.gmao.commun.reporting.classe.ChampEtatOT.<init>(java.lang.String, java.lang.String, java.lang.String, java.util.Date, java.util.Date)Query: ReportQuery(referenceClass=TravOrdreTravail jpql="SELECT NEW dz.elit.gmao.commun.reporting.classe.ChampEtatOT( ot.numero, uo.denominationFr, ot.etat, ot.dateDebutReelle , ot.dateFinReelle, :dateParam1, :dateParam2, :dateParam3) FROM TravOrdreTravail ot JOIN ot.uniteOrganisationnellle uo")
我认为将参数放入select子句是不可能的,所以有人有想法,构造函数方法如下:
public ChampEtatOT(String numero, String denominationFr, String etat, Date dateDebutReelle, Date dateFinReelle, Date dateParam1, Date dateParam2, Date dateParam3) {
this.numero = numero;
this.denominationFr = denominationFr;
if (etat.equals("OUV")) {
if (dateDebutReelle.before(dateParam1)) {
etatEntreeSortie = "En instance debut du mois";
} else {
if (dateDebutReelle.before(dateParam2)) {
etatEntreeSortie = "En instance fin du mois";
} else {
if (dateDebutReelle.after(dateParam1) && dateDebutReelle.before(dateParam2)) {
etatEntreeSortie = "Entree/Mois";
}
}
}
}
}
答案 0 :(得分:1)
我认为在构造函数中引用参数是不可能的。
在你的情况下,它抛出一个NoSuchMethodexeption:它意味着,ChampEtatOT
类中没有当前签名的方法(5个参数而不是8个)
你可以参考这个答案=&gt; Passing a parameter in a jpql query select
因此,尝试检索所有数据,然后创建一个过滤器方法,以在ResultList的etatEntreeSortie
类中设置所有ChampEtatOT
值
答案 1 :(得分:1)
问题解决了,正如你所建议的那样bRIMO Bor它不可能在SELECT子句中传递参数,所以我已经在List中检索了所有结果,而不是根据日期date1,date2,date3过滤结果
Query query = em.createQuery("SELECT NEW ChampEtatAteliers"
+ "( ot.numero, uo.denominationFr, ot.etat, ot.dateDebutReelle, ot.dateFinReelle) "
+ "FROM ordre ot JOIN ot.unite uo");
List<ChampEtatAteliers> champEtatAtelierses = query.getResultList();
for (ChampEtatAteliers champEtatAtelierse : champEtatAtelierses) {
if (champEtatAtelierse.getDateDebutReelle().compareTo(date1) >= 0 && champEtatAtelierse.getDateDebutReelle().compareTo(date2) <= 0) {
champEtatAtelierList2.add(new ChampEtatAteliers(champEtatAtelierse.getNumero(), champEtatAtelierse.getDenominationFr(), "Entree/Mois"));
}
if (champEtatAtelierse.getEtat().equals("OUV")) {
if (champEtatAtelierse.getDateDebutReelle().compareTo(date1) < 0) {
champEtatAtelierse.setEtatEntreeSortie("En instance début du mois");
} else {
if (champEtatAtelierse.getDateDebutReelle().compareTo(date2) <= 0) {
champEtatAtelierse.setEtatEntreeSortie("En instance fin du mois");
}
}
}
}
答案 2 :(得分:0)
显然,constructor_expression ::= NEW constructor_name ( constructor_item {, constructor_item}* )
constructor_item ::= single_valued_path_expression | scalar_expression | aggregate_expression |
identification_variable
scalar_expression ::= simple_arithmetic_expression | string_primary | enum_primary |
datetime_primary | boolean_primary | case_expression | entity_type_expression
string_primary ::= state_field_path_expression | string_literal |
input_parameter | functions_returning_strings | aggregate_expression | case_expression
确实允许将参数作为构造函数参数传递。
{{1}}
即 scalar_expression 可以是 string_primary ,它可以是 input_parameter 。因此,您的JPA提供程序不符合JPA规范,您应该提出错误。