Question

我有以下网址路径模式

/posts(/:id:)?

用参数填充它并将它们与模式匹配的最佳方法是什么？

首先，我将相应的参数模式（:id:）替换为提供的实际模式并构建透视输出URL

preg_replace_callback('~:([^:]+):~', function($match) {
    //aggregate the match &&
    //1) return the output url ||
    //2) return the output pattern
}, $pattern);

根据参数，它可能与/posts/3类似。其次，我再次调用preg_replace_callback来构建输出模式。最后，我将两个结果preg_match进行比较，以确保细分有效性。伪代码

argument => 3,     outputUrl     => /posts/3
pattern  => [\d]+, outputPatterm => /posts(/[\d]+)?

preg_match(outputPattern, outputUrl) => matches...

实施例

$this->patterns = [
    'id' => '[\d]+'
];

$this->arguments = [
    'id' => 3
];

$pattern = '/posts(/:id:)?';

$outputPattern = preg_replace_callback('~:([^:]+):~', function($match){
    return $this->patterns[$match[1]];
}, $pattern);

$outputUrl = preg_replace_callback('~:([^:]+):~', function($match){
    return $this->arguments[$match[1]];
}, $pattern);

if (preg_match('~^'.$outputPattern.'$~', $outputUrl)) {
    //nice, they match. Still two preg_* methods used
}

正则表达式匹配模式来构建URL

0 个答案: