Question

我是编程新手。当我需要发送一个json视图时，我有一个任务：

{
  "code"  : 200,
  "error" : 0,
  "data" : {
      "sLogo" : "http://test.com/images/logo.png",
      "aWinners": [
          {
           "sName": "name"
          }
       ]
   }
}

我现在如何管理数据，但我不了解如何管理code和error。你能帮我一下吗？ Thx提前和抱歉我的英语。我的想法是，我需要发送这个json的视图，但我不明白mus包含code

Answer 1

您可以使用json_decode()获取代码和错误值。

$json = '{"code"  : 200,"error" : 0,"data" : {"sLogo" : "http://test.com/images/logo.png","aWinners": [{"sName": "name"}]}}';
$arr = json_decode($json, TRUE);
echo $arr['code'];
echo $arr['error'];

Answer 2

Note: Just pass the json as string from controller to your view and then decode your data in the view as per your requirement.
In Controller
<?php
$json = '{"code"  : 200,"error" : 0,"data" : {"sLogo" : "http://test.com/images/logo.png","aWinners": [{"sName": "name"}]}}';
?>
In View
<?php
$arr = json_decode($json, TRUE);
$code= $arr['code'];
$error= $arr['error'];
?>

管理json中的代码和错误

2 个答案: